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7. A pump is pumping water at 50 gal/min; P= 70 psi. The efficiency of the pump is 0.73. Compute the hydraulic horsepower (hp) of the pump.

7. A pump is pumping water at 50 gal/min; P= 70 psi. The efficiency of the pump is 0.73. Compute the hydraulic horsepower (hp) of the pump.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Question 7

6. While drilling, the mud is being circulated at 2.5 bbl/minute. The surface pressure seen at the pumps is 2,500 psi. Hydraulic horsepower = flow rate * Pressure = q* P 7. a. b. d. What is the hydraulic power required for the mud pump in horsepower (HP)? Assuming the mud pumps run on diesel, and assuming the pumps are 45% efficient (only 45% of the power of the fuel creates pumping power), how much fuel would this one mud pump consume per week if operating 24 hrs/day under these conditions? Assume pumps are 45% efficient, 55% of the power goes to waste, so the power needed is 1/efficiency, or Estimate the bottomhole pressure at 7,000 ft assuming the mud weight is 11 ppg and a surface pressure of 2,500 psi. (the bottomhole pressure is the sum of a) the surface pressure and b) the pressure caused by the column of mud in the wellbore) Assuming we wanted to keep the same bottomhole pressure, we could reduce the surface pressure by increasing the mud weight. What mud weight would be required to reduce the surface pressure to 500 psi but still keep the same bottomhole pressure as (c)? A pump is pumping water at 50 gal/min; P= 70 psi. The efficiency of the pump is 0.73. Compute the hydraulic horsepower (hp) of the pump.
Transcribed Image Text:6. While drilling, the mud is being circulated at 2.5 bbl/minute. The surface pressure seen at the pumps is 2,500 psi. Hydraulic horsepower = flow rate * Pressure = q* P 7. a. b. d. What is the hydraulic power required for the mud pump in horsepower (HP)? Assuming the mud pumps run on diesel, and assuming the pumps are 45% efficient (only 45% of the power of the fuel creates pumping power), how much fuel would this one mud pump consume per week if operating 24 hrs/day under these conditions? Assume pumps are 45% efficient, 55% of the power goes to waste, so the power needed is 1/efficiency, or Estimate the bottomhole pressure at 7,000 ft assuming the mud weight is 11 ppg and a surface pressure of 2,500 psi. (the bottomhole pressure is the sum of a) the surface pressure and b) the pressure caused by the column of mud in the wellbore) Assuming we wanted to keep the same bottomhole pressure, we could reduce the surface pressure by increasing the mud weight. What mud weight would be required to reduce the surface pressure to 500 psi but still keep the same bottomhole pressure as (c)? A pump is pumping water at 50 gal/min; P= 70 psi. The efficiency of the pump is 0.73. Compute the hydraulic horsepower (hp) of the pump.
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