7. A soil profile consisting of three layers is shown in the figure. Calculate the values of the total stress, effective stress ad pore water pressure at points A, B. C, and D for the following cases. In each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are given below: Page 3 of 4 HI Layer 1 Groundwater table Layer 2 Layer 3 Dry sand Sand Clay I Rock Soil parameters Y = 110 lb/ft Layer no. Thickness H, = 7 ft H = 12 ft н, — 6 ft 2 Yaat = 121 lb/ft 3 Yt = 118 lb/ft³ 1 H, = 5 m e = 0.7; G, = 2.69 %3! e - 0.55; G, - 2.7 w = 38%;e = 1.2 II, = 8 m 3 H, = 3 m %3D Y = 16 kN/m 18 kN/m 1 H, = 3 m %3! H; = 6 m Yat H, = 2.5 m Yat 17 kN/m? %3D 2. 3.

Principles of Foundation Engineering (MindTap Course List)
9th Edition
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Author:Braja M. Das, Nagaratnam Sivakugan
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Chapter2: Geotechnical Properties Of Soil
Section: Chapter Questions
Problem 2.13P
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7. A soil profile consisting of three layers is shown in the figure. Calculate the values of the total
stress, effective stress ad pore water pressure at points A, B, C, and D for the following cases. In
each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are
given below:
Page 3 of 4
Layer 1
Groundwater table
Layer 2
Layer 3
Dry sand
Sand
Clay
Rock
Layer no.
Thickness
Soil parameters
1
Y = 110 lb/ft³
121 Ib/ft
H = 7 ft
2
%3D
Yat =
3
H, = 6 ft
Yeat = 118 lb/ft³
e = 0.7; G, = 2.69
e = 0.55; G, = 2.7
w = 38%;e = 1.2
%3D
1
H = 5 m
II, = 8 m
%3D
3
H, = 3 m
1
H, = 3 m
Y = 16 kN/m
18 kN/m
2
H¸ = 6 m
Yat
3
H, = 2.5 m
17 kN/m
%3D
Ysat
%3D
2.
Transcribed Image Text:7. A soil profile consisting of three layers is shown in the figure. Calculate the values of the total stress, effective stress ad pore water pressure at points A, B, C, and D for the following cases. In each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are given below: Page 3 of 4 Layer 1 Groundwater table Layer 2 Layer 3 Dry sand Sand Clay Rock Layer no. Thickness Soil parameters 1 Y = 110 lb/ft³ 121 Ib/ft H = 7 ft 2 %3D Yat = 3 H, = 6 ft Yeat = 118 lb/ft³ e = 0.7; G, = 2.69 e = 0.55; G, = 2.7 w = 38%;e = 1.2 %3D 1 H = 5 m II, = 8 m %3D 3 H, = 3 m 1 H, = 3 m Y = 16 kN/m 18 kN/m 2 H¸ = 6 m Yat 3 H, = 2.5 m 17 kN/m %3D Ysat %3D 2.
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