7. (a) The area of the triangle AABC is 25/3 cm2. If ZA = 30° and sidelengths b the sidelengths b and c. (b) Given triangle AABC with side lengths a = (c) Find the area of the shaded region, given that the central angle 0 8 inches. = c, then find 6cm and c= 4cm, find the area of the triangle. 120° and the radius of the circle is 6ст, b — (d) An isosceles triangle has an area of 100 cm2, and the angle between the two equal sides is 0 = 5т What is the length of the two equal sides?

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter1: Line And Angle Relationships
Section1.2: Angles And Their Relationships
Problem 37E: Draw a triangle with three acute angles. Construct angle bisectors for each of the three angles. On...
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Part D

7. (a) The area of the triangle AABC is 25/3 cm2. If ZA = 30° and sidelengths b
the sidelengths b and c.
(b) Given triangle AABC with side lengths a =
(c) Find the area of the shaded region, given that the central angle 0
8 inches.
= c, then find
6cm and c=
4cm, find the area of the triangle.
120° and the radius of the circle is
6ст, b —
(d) An isosceles triangle has an area of 100 cm2, and the angle between the two equal sides is 0 =
5т
What
is the length of the two equal sides?
Transcribed Image Text:7. (a) The area of the triangle AABC is 25/3 cm2. If ZA = 30° and sidelengths b the sidelengths b and c. (b) Given triangle AABC with side lengths a = (c) Find the area of the shaded region, given that the central angle 0 8 inches. = c, then find 6cm and c= 4cm, find the area of the triangle. 120° and the radius of the circle is 6ст, b — (d) An isosceles triangle has an area of 100 cm2, and the angle between the two equal sides is 0 = 5т What is the length of the two equal sides?
Expert Solution
Step 1 (d)

The area of a triangle can be expressed using the lengths of two sides and the sine of the included angle as:

Advanced Math homework question answer, step 1, image 1

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