Return the launch height to 1 meter above ground level and assume any angle to launch aprojectile.Conduct several trials to answer the following questions.7. Does launching a projectile at an angle effecti)the path or trajectory,ii)horizontal velocity (vx),iii) vertical velocity (vy)iv) acceleration compared to that of a projectile launched horizontally? 8. At what point in the projectile's trajectory is the velocity vector entirely horizontal (i.e., thevertical component of velocity is zero)?using the Single Step buttonIf necessary, slow the simulation down9. TRUE or FALSE: The acceleration of projectile is 0 m/s at the peak of the trajectory. Howdo you justify your answer?10. Pick a launch speed and angle and compare the time required for the projectile to rise to thepeak of its trajectory to the time for the projectile to fall from the peak of its trajectory.The Single Step button and the Vector display can be used to assist in your measurements.Repeat for other launch angles if necessary. Describe your findings.

Name: Return the launch height to 1 meter above ground level and assume any
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Description: Return the launch height to 1 meter above ground level and assume any angle to launch aprojectile.Conduct several trials to answer the following questions.7. Does launching a projectile at an angle effecti)the path or trajectory,ii)horizontal veloci

7. 1. Trajectory equation: y=tanθ·x-g2u2cos2θ·x2 It depends on θif angle is small, path is less…

Answered: 7. Does launching a projectile at an…

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Return the launch height to 1 meter above ground level and assume any angle to launch a
projectile.
Conduct several trials to answer the following questions.
7. Does launching a projectile at an angle effect
i)
the path or trajectory,
ii)
horizontal velocity (vx),
iii) vertical velocity (vy)
iv) acceleration compared to that of a projectile launched horizontally?

8. At what point in the projectile's trajectory is the velocity vector entirely horizontal (i.e., the
vertical component of velocity is zero)?
using the Single Step button
If necessary, slow the simulation down
9. TRUE or FALSE: The acceleration of projectile is 0 m/s at the peak of the trajectory. How
do you justify your answer?
10. Pick a launch speed and angle and compare the time required for the projectile to rise to the
peak of its trajectory to the time for the projectile to fall from the peak of its trajectory.
The Single Step button and the Vector display can be used to assist in your measurements.
Repeat for other launch angles if necessary. Describe your findings.

Expert Solution

Step 1

1. Trajectory equation:

$y = \tan θ \cdot x - \frac{g}{2 u^{2} \cos^{2} θ} \cdot x^{2}$

It depends on $θ$ if angle is small, path is less steeper.

Yes angle affects path or trajectory of projectile.

2. Horizontal velocity:

$v_{x} = u \cos θ$

It also depends on angle so it is affected by angle.

But horizontal velocity is constant as gravity only affects vertical velocity.

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