7. [Geogebra Question] Let's use Geogebra to find the area of the region enclosed by the graphs of the following two functions p(x) = x² – 6x – 3, r(x) = -2x2 + 5x + 7 (a) Define the given functions p(x) and r(x). Graphs of the functions are shown automatically on the plot area. Adjust the plot area so that the region enclosed by the two graphs is clearly visible. This plot should be included in your submission. (b) Find the values of x where the graphs of p(x) and r(x) intersect. Equation f(x) = 0 can be solved in Geogebra using the command Solve(f(x)=0,x) (c) Find the area of the region enclosed by the two graphs. Definite integral f(x)dx can be computed in Geogebra using the command Integral (f(x),x,a,b)
7. [Geogebra Question] Let's use Geogebra to find the area of the region enclosed by the graphs of the following two functions p(x) = x² – 6x – 3, r(x) = -2x2 + 5x + 7 (a) Define the given functions p(x) and r(x). Graphs of the functions are shown automatically on the plot area. Adjust the plot area so that the region enclosed by the two graphs is clearly visible. This plot should be included in your submission. (b) Find the values of x where the graphs of p(x) and r(x) intersect. Equation f(x) = 0 can be solved in Geogebra using the command Solve(f(x)=0,x) (c) Find the area of the region enclosed by the two graphs. Definite integral f(x)dx can be computed in Geogebra using the command Integral (f(x),x,a,b)
Chapter4: Rational Functions And Conics
Section: Chapter Questions
Problem 11T: A triangle is formed by the coordinate axes and a line through the point (2,1), as shown in the...
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