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- Brainberene, a compound isolated from an organic chemist’s brain, has the molecular formula C16 H26. When Brainberene is subjected to catalytic hydrogenation using an excess of hydrogen, 1 mol of Brainberene absorbs 3 mol of hydrogen and produces B: C16 H32. 1) What is the element of unsatuation (IHD) of Brainberene? 2) How many double bonds and rings do Brainberene has? Laboratory experiments revealed that Brainberene has no triple bonds. 3) What is the IHD of B? d) How many double bonds and rings does B has? 121,4-Pentadiene (CH2=CH-CH2-CH=CH2) is a liquid at room temperature and has a density of 0.66 g/mL and molar mass of 68.12 g/mol. In a laboratory experiment, 3.80 mL of this compound was treated with 4.80 mL of conc. H2SO4 (100% w/w; molar mass 98.08 g/mol). Note that the density of conc. H2SO4 is 1.84 g/mL. The resulting sulfate ester was then treated with 1.20 mL of water (molar mass 18.02 g/mol) affording, after work- up, 2,4-pentanediol (molar mass 104.15 g/mol) as the crude product. The crude product was then purified by simple distillation, which yielded 2.00 g of pure product. What is the theoretical yield of 2,4-pentanediol expressed in grams? Show calculations. What is the percentage yield of pure 2,4-pentanediol?1,4-Pentadiene (CH2=CH-CH2-CH=CH2) is a liquid at room temperature and has a density of 0.66 g/mL and molar mass of 68.12 g/mol. In a laboratory experiment, 3.80 mL of this compound was treated with 4.80 mL of conc. H2SO4 (100% w/w; molar mass 98.08 g/mol). Note that the density of conc. H2SO4 is 1.84 g/mL. The resulting sulfate ester was then treated with 1.20 mL of water (molar mass 18.02 g/mol) affording, after work- up, 2,4-pentanediol (molar mass 104.15 g/mol) as the crude product. The crude product was then purified by simple distillation, which yielded 2.00 g of pure product. a. Provide a balanced chemical equation to show the reaction between 1,4-pentadiene and sulfuric acid. Do not use molecular formulas in the chemical equation except for sulfuric acid. b. What reactant is the limiting reagent in this chemical equation? Show calculations to support your answer.
- Rank the following groups in order of decreasing priority. −H, −CH3, −Cl, −CH2Clgive a name of any compound which is isostructural with XeF2Consider the compounds 1-pentanol,CH3-CH2-CH2-CH2-CH2-OH, melting point -78C boiling point 138C, MW=88.15. 1,6-hexanediol ,HO-CH2-CH2-CH2-CH2-CH2-CH2-OH, mp 42C,bp=250C.MW=118.18. The compound 1,6-hexanediol is more soluble in water than 1-pentanol is. This is because 1,6-hexanediol.... 1) has more carbon atoms 2)has a higher molecular weight 3)has more -OH groups 4)is a solid at room temperature
- Propanal, an aldehyde with the formula CH3CH2CHO, and n-propylamine have identical molecular weights (59 amu) and identical boiling points (49 C) Which molecule do you expect to be more polar and why?Assign a priority order (from least to highest priority) to each of the following sets of groups: I. -OCH II. -NH(CH3)2 III. CH2NH2 IV. -OH A. IV, I, III, II B. III, II, IV, I C. II, III, IV, I D. III, IV, I, IIWhat is the correct order for the strenth of IMFA of the following substances? LiCl < H2O < C8H18 H2O < LiCl< C8H18 C8H18 < LiCl < H2O C8H18 < H2O < LiCl
- Rank the following groups in order of decreasing priority. a.−F, −NH2, −CH3, −OH b.−CH3, −CH2CH3, −CH2CH2CH3, −(CH2)3CH3 c.−NH2, −CH2NH2, −CH3, −CH2NHCH3 d.−COOH, −CH2OH, −H, −CHO e.−Cl, −CH3, −SH, −OH f.−C≡CH, −CH(CH3)2, −CH2CH3, −CH=CH2what structure would be represented HNMR with a singlet at 7.29 being caused by 2 hydrogens and a doublet at 3.88 being caused by 9 hydrogens?1. Using Br2 in C2H4Br2 will result in HBr and ______. a. C2H3Cl3 b. C2H4Cl3 c. C2H2Cl3 d. none of the above 2. How many halogenation are posible in propane? a. 3 b. 8 c. 6 d. 10 3.Sulfonation of pentane will result in ________ and water. a. C5H11SO3H b. C5H12SO3H c. C5H14SO3H d. none of the above 4.Nitration of hexane will result in ________ and water. a. C6H13SO3H b. C6H15NO2 c. C6H13NO2 d. C6H14NO2 5.How many moles of O2 in heating a C12H26 (dodecane) a. 27 b. 37 c. 24 d. none of the above