7. In pea plants, green seeds (G) are dominant over yellow seeds (g). In a cross between two plants both heterozygous for seed color, the following was observed: (Show all work) Green: 4400 Yellow: 1624 NULL: Does the data fit the predicted phenotypic ratio?

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Chapter3: Transmission Of Genes From Generation To Generation
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Problem 22QP: More Crosses with Pea Plants: The Principle of Independent Assortment In pea plants, long stems are...
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Answer 7 with the table please
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7. In pea plants, green seeds (G) are dominant over yellow seeds (g). In a cross between two plants both
heterozygous for seed color, the following was observed: (Show all work)
Green: 4400
Yellow: 1624
NULL:
Does the data fit the predicted phenotypic ratio?
8. In peas, tall plants (T) are dominant over short plants (t). In the P generation, a plant homozygous for tall height
is crossed with a short plant. The resulting F1 plants are crossed. The plant heights of the observed F2 generation
were: (Show all work) 3:1
Tall: 5474
Short: 1850
NULL
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Transcribed Image Text:Format Tools Add-ons Help Last edit was 2 minutes ago Normal text Times BIUA 10 + 1 7. In pea plants, green seeds (G) are dominant over yellow seeds (g). In a cross between two plants both heterozygous for seed color, the following was observed: (Show all work) Green: 4400 Yellow: 1624 NULL: Does the data fit the predicted phenotypic ratio? 8. In peas, tall plants (T) are dominant over short plants (t). In the P generation, a plant homozygous for tall height is crossed with a short plant. The resulting F1 plants are crossed. The plant heights of the observed F2 generation were: (Show all work) 3:1 Tall: 5474 Short: 1850 NULL Support | Schoology Blog | PRIVACY POLIC !!!
Expert Solution
Step 1

Biology homework question answer, step 1, image 1

  A a
A AA Aa
a Aa aa

 

A = Yellow

a = green

Expected Phenotypic ratio 3:1

Yellow : green 

Phenotype Observed (O) Expected (E) O-E (O-E)2 Biology homework question answer, step 1, image 2
Yellow 4400 6024(.75) 4158 -118 13924 3.08
Green 1624 6024(.25) 1506 -118 13924 9.24
Totals 6024 6024     12.34

 

         

            n=2-1=1      P=3.84                 139244518=3.08      Hence, No data         139241506=9.24      does not fit predicted phenotype as           12:32>3.84.

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