7. Is this graph proportional? * 200 180 160 140 120 100 80 60 40 20 1 2 4 5 6 7 8.9 10 NUMBER OF WEEKS The graph is proportional O The graph is non proportional ACCOUNT BALANCE
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- a) A C-chart is to be constructed for the count of surface defects in 2000 square meters of 40-kg Kraft paper. If 55 lots had a total of 550 defects. Determine the trial central line and control limits.b) An (np) chart is to be established on a painting process that is in statistical control. If 60 pieces are to be inspected every 3 hours and the fraction non-conforming is 0.06, determine the central line and control limitsWilliam Profit is studying companies going public for the first time. He isparticularly interested in the relationship between the size of the offering and theprice per share. A sample of 15 companies that recently went public revealed the following information: y x 10.8 9 11.3 94.4 11.2 27.3 11.1 179.2 11.1 71.9 11.2 97.9 11 93.5 10.7 70 11.3 160.7 10.6 96.5 10.5 83 10.3 23.5 10.7 58.7 11 93.8 10.8 34.4A process manufactures plastic tapes in batches of 50 units (tapes). The inspection records of the last 30 batches produced during one week individually by 30 workers of this process revealed the following results: (IMAGE) The production supervisor, will award a prize to the most outstanding worker of the week and in addition a party will be given in his honor. a) Draw a graph of worker vs. % of non-conforming product. b) What is the average quality level of the week obtained by the workers in this process? c) To whom should the award be assigned?Who was the best worker? Who was the worst worker? d) What would you do to improve the results of this process?
- The authors of a paper compared two different methods for measuring body fat percentage. One method uses ultrasound, and the other method uses X-ray technology. Body fat percentages using each of these methods for 16 athletes (a subset of the data given in a graph that appeared in the paper) are given in the accompanying table. You can assume that the 16 athletes who participated in this study are representative of the population of athletes. Athlete X-ray Ultrasound 1 5.00 4.25 2 16.00 12.75 3 9.25 9.00 4 12.00 11.75 5 17.25 17.00 6 29.50 27.50 7 5.50 6.50 8 6.00 6.75 9 8.00 8.75 10 9.50 10.50 11 9.25 9.50 12 11.00 12.00 13 12.00 12.25 14 14.00 15.50 15 17.00 18.00 16 18.00 18.25 Use these data to estimate the difference in mean body fat percentage measurement for the two methods. Use a confidence level of 95%. (Use ?d = ?X-ray − ?ultrasound. Round your answers to three decimal places.) , % Interpret the interval in context.…The authors of a paper compared two different methods for measuring body fat percentage. One method uses ultrasound, and the other method uses X-ray technology. Body fat percentages using each of these methods for 16 athletes (a subset of the data given in a graph that appeared in the paper) are given in the accompanying table. You can assume that the 16 athletes who participated in this study are representative of the population of athletes. Athlete X-ray Ultrasound 1 5.00 4.50 2 15.00 11.75 3 9.25 9.00 4 12.00 11.75 5 17.25 17.00 6 29.50 27.50 7 5.50 6.50 8 6.00 6.75 9 8.00 8.75 10 16.50 17.50 11 9.25 9.50 12 11.00 12.00 13 12.00 12.25 14 14.00 15.50 15 17.00 18.00 16 18.00 18.25 Use these data to estimate the difference in mean body fat percentage measurement for the two methods. Use a confidence level of 95%. (Use ?d = ?X-ray − ?ultrasound. Round your answers to three decimal places.) , % Interpret the interval in…The authors of a paper compared two different methods for measuring body fat percentage. One method uses ultrasound, and the other method uses X-ray technology. Body fat percentages using each of these methods for 16 athletes (a subset of the data given in a graph that appeared in the paper) are given in the accompanying table. You can assume that the 16 athletes who participated in this study are representative of the population of athletes. Athlete X-ray Ultrasound 1 5.00 4.25 2 12.00 8.75 3 9.25 9.00 4 12.00 11.75 5 17.25 17.00 6 29.50 27.50 7 5.50 6.50 8 6.00 6.75 9 8.00 8.75 10 9.50 10.50 11 9.25 9.50 12 11.00 12.00 13 12.00 12.25 14 14.00 15.50 15 17.00 18.00 16 18.00 18.25 Use these data to estimate the difference in mean body fat percentage measurement for the two methods. Use a confidence level of 95%. (Use ?d = ?X-ray − ?ultrasound. Round your answers to three decimal places.) , % Interpret the interval in…
- Suppose the customers arrive at a Poisson rate of on eper every 12 minutes, and that the service time is exponential at a rate of one service per 8 minutes. What are the average number of customers in the system(L) and the average time a customer spends in the system(W)? Now suppose that the arrival rate increases 20 percent.What is the corresponding change in L and W?Suppose the customers arrive at a Poisson rate of on eper every 12 minutes, and that the service time is exponential at a rate of one service per 8 minutes. What are the average number of customers in the system(L) and the average time a customer spends in the system(W)?The Admission director for a college far from mart and town believes that an inverse relationship exists between a private college's average discount rate(determined by the average amount of scholarships students receive) and the annual yield (the percentage of admitted students who actually attend). The Director's independent variable is a private college's discount rate measured as a percentage, and the dependent variable is the college's annual yield measured as a percentage. The following results were obtained for a sample of 30 private colleges: x- Discount rate(percentage) - range: 35 to 72 percent y- Annual Yield(percentage) - range: 12 o 81 percent Σxi = 1612 Σyi = 898 Σxiyi = 44,377 Σxi2 = 89,790 Σyi2 = 35,704 a. Calculate the sample regression line's slope estimate. Interpret the sample regression line's slope estimate. b. Calculate the sample regression line's intercept estimate. Interpret the sample regression line's intercept estimate. Assume the following sum of…
- Suppose 24% of students at Florida University are business students. Of those, 28% are Econ majors.What percent of Florida University students are Econ majors? Round your answer to three decimal places.A) What is the purpose of the “callout bubble” in the bottom right-hand corner of the graph, showing a tiny red square inside the yellow square? Why do you suppose the author felt the need to use a callout bubble? B) Data from this source show that the rate of symptomatic infection with COVID for people who have been vaccinated is about 100 infections per 102,000 vaccinations. As of July 30, 2021, data show that164,000,000 Americans have been fully vaccinated. How many of these vaccinated Americans would be expected to become infected with COVID and display symptoms? C) Data from this source show that the rate of death from COVID for people who have been vaccinated is about 1 death per 102,000 vaccinations. As of July 30, 2021, data show that 164,000,000 Americans have been fully vaccinated. How many of these vaccinated Americans would be expected to die from COVID?The diagram below illustrates the electricity generation in ten countries during 2011. (a) Based on the data in the graph, identify one of the fuel sources that in 2011 was intermediate in contribution among the ten countries in the amount of electricity generated. (b) Based on the data in the graph, identify the country that produced a higher percentage of its electricity in 2011 from nonhydroelectric renewables than any other country. (c) Based on the data in the graph, describe one environmental problem in South Korea that could result if its total electricity generation was increased by 10 percent with its most-used fuel source. (d) Based on the data in the graph, propose a solution to reduce an environmental problem linked to the primary means of electricity generation in Brazil, other than reduced use of that resource. (e) The ecological footprint of an average individual living in Canada is seven times larger than the ecological footprint of an average individual living in…