#7 ** Example 15: An Application. The miter angle is the angle at which a saw or miterbox must be set to cut a piece of stock to form a joint. It is equal to half the anglebetween the pieces to be joined. Find the miter angle for the pentagonal window inFig. 6-59.Solution: The sum of the angles of the pentagon are, with n = 5.sam of angles = (-2)180°=(5-2)180-540Each interior angle is then 540/5= 108. The miter angle is half of that, on0=54°Exercise 3 Quadrilaterals1. Find the area and perimeter of(a) a square of side 5.83 in.(b) a square of side 4.82 m.(c) a rectangle measuring 384 cm x 734 cm.(d) a rectangle measuring 55.4 in. by 73.5 in.1902. Find the area of(a) a parallelogram whose base is 4.52 ft and whose altitude is 2.95 ft.(b) a parallelogram whose base is 16.3 m and whose altitude is 22.6 m(c) a rhombus whose base is 14.2 cm and whose altitude is 11.6 cm(d) a rhombus whose base is 382 in, and whose altitude is 268 in.(e) a trapezoid whose bases are 3.83 m and 2.44 m and whose altitude is 1.86 m.(f) a trapezoid whose bases are 33.6 ft and 24.7 ft and whose altitude is 15.3 ft.Applications3. What will be the cost, to the nearest dollar, of flagging a sidewalk 312 ft longand 6.5 ft wide, at $13.50 per square yard?4. How many 9-in-square tiles will cover a floor 48 ft by 12 ft?5. What will it cost to carpet a floor, 6.25 m by 7.18 m, at $7.75 per square meter?6. How many rolls of paper, each 8.00 yd long and 18.0 in. wide, will paper thesides of a room 16.0 ft by 14.0 ft and 10.0 ft high, deducting 124 ft² for doorsand windows?3608FIGURE 6-6120.0Chapter 6 Geometry7. What is the cost of plastering the walls and ceiling of a room 40 ft long. 36 ftwide, and 22 ft high, at $8.50 per square yard, allowing 1375 ft² for doors,windows, and baseboard?8. What will it cost to cement the floor of a cellar 25.3 ft long and 18.4 ft wide,at $3.50 per square foot?7209. Find the cost of lining a topless rectangular tank 68 in. long, 54 in. wide, and 48 indeep with zinc, weighing 5.2 lb per square foot, at $1.55 per pound installed.10. A parcel of land lies between two parallel streets, Fig. 6-60. How many acres willremain in the parcel after the strip shown is taken for a new street? (1 acre-43,560 ft²)0New StreetFIGURE 6-5875.0FIGURE 6-59845Street/Street (350 fFIGURE 6-6011. Brick Requirement. Estimate the number of bricks needed for a wall 13 x 18 f.having one door 4 ft Xx 9 ft and two windows each 3 ft x 6 ft. Each brick has facesmeasuring 8 x 2¹/4 inches, with half-inch joints between bricks.12. Squares of Roofing Material. Roofing material is often specified in squares,where one square equals 100 ft². How many squares of shingles are needed tocover the roof of Fig. 6-61, neglecting waste?13. Miter Angles: Calculate the miter angle for a(a) triangular window (equilateral)(b) square or rectangular frame(c) hexagonal window(d) octagonal wall clock6-4 The CircleA circle, Fig. 6-62, is a plane curve in which all points are at a given distance(called the radius) from a fixed point (called the center). The diameter is twice theradius. The diameter cuts the circle into two semicircles.Circumference and Pi (#)The circumference of a circle is its total length, or the distance around.■ Exploration:Try this. Wrap a strip of paper around a circular object, such as a jar lid, and markthe point where it starts to overlap. The length from the mark to the end of the strip

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Answer of question number 7 is provided here.

7. What is the cost of plastering the walls and ceiling of a room 40 ft long. 36 ft wide, and 22 ft high, at $8.50 per square yard, allowing 1375 ft² for doors, windows, and baseboard?