●1 inch = exactly 2.54 cm1 foot = exactly 12 inches1 mile = 1609 meters = 1.609 km● 1 hour = exactly 60 minutes1 minute = exactly 60 seconds1 m³ = exactly 1000 L (1000 liters)1 acre exactly 43,560 square feetRound answers to 3 sig figs. Solutions to 6 of these questions are in the videos cited at the end of thissection. 7.20 mm ¹/2 x () × (_cm¹/25.20 mL X<(—7.20 mm²¹/³ × (-) × (—) × (X_cm¹/3x (-) x (-) =9.81 meters/second² × (-) x (x (—) =x_km/min²=(¯▬▬) × (¯¯)×(—cm³-)x() =

Answered: Image /qna-images/answer/380ac013-2079-4dd8-9478-3c8858822a0e.jpg

Answered: 7.20 mm ¹/² x ( ) × (—)×(▬▬ _cm¹/2 7.20…

Mathematics For Machine Technology

8th Edition

ISBN:9781337798310

Author:Peterson, John.

Publisher:Peterson, John.

Chapter10: Rounding Decimal Fractions And Equivalent Decimal And Common Fractions

Section: Chapter Questions

Problem 29A

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The solution of the following problems requires more than one formula and the rearrangement of formulas. Use C=3.1416DN12 or DN12 for customary units and C=3.1416DN1000 or DN1000 for metric units. N=12C3.1416D or 12CD for customary units and N=1000C3.1416D or 1000CD for metric units. T=LFN A carbide milling cutter is used for machining a 560.00-millimeter length of stainless steel. The cutting time is 11.95 minutes, the cutting speed is 60.000 meters per minute, and the feed is0.250 millimeter per revolution. What is the diameter of the carbide milling cutter? Round the answer to 1 decimal place.
The solution of the following problems requires more than one formula and the rearrangement of formulas. Use C=3.1416DN12 or DN12 for customary units and C=3.1416DN1000 or DN1000 for metric units. N=12C3.1416D or 12CD for customary units and N=1000C3.1416D or 1000CD for metric units. T=LFN A combination drilling and countersinking operation on bronze round stock is performed on an automatic screw machine. The length of cut per piece is 134 inches.The total cutting time for 2300 pieces is 612 hours running at 1600 rpm. What is the tool feed in inches per revolution? Round the answer to 3 decimal places.
The solution of the following problems requires more than one formula and the rearrangement of formulas. Use C=3.1416DN12 or DN12 for customary units and C=3.1416DN1000 or DN1000 for metric units. N=12C3.1416D or 12CD for customary units and N=1000C3.1416D or 1000CD for metric units. T=LFN Aluminum baseplates are produced that are 158 inches thick. Six 14 inch-diameterholes are drilled in each plate using a feed of 0.004 inch per revolution and a cutting speed of 300 feet per minute. Setup and handling time is estimated at 0.5 minute per piece. What is the total number of hours required to produce 850 aluminum baseplates? Round the answer to 1 decimal place.
Solve the following applied right triangle problems. Compute linear values to 3 decimal places, customary unit angles to the nearer minute, and metric angles to the nearer hundredth degree. 24. Determine dimension x. All dimension are in millimeters. .
A 60° slot has been machined in a fixture. The slot is checked by placing a pin in the slot and indicating the distance between the top of the fixture and the top of the pin as shown. Compute distance H to 3 decimal places by using this formula. All dimensions are in inches. H=1.5D0.866W
In each of the following problems, refer to the given figure, solve for the unknowns, and check. Find the distances between the indicated holes. All dimensions are in millimeters. a. Hole 1 to hole 2 b. Hole 2 to hole 3 C. Hole 3 to hole 4 d. Hole 4 to hole 5 e. Hole 5 to hole 6 f. Hole 2 to hole 4 g. Hole 3 to hole 6

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7.20 mm ¹/² x ( ) × (—)×(▬▬ _cm¹/2 7.20 mm¹/³ × (-) × (¯) × (▬▬▬) = X sonunt 002 _cm¹/3 9.81 meters/second² × (-) x (x (—) = _km/min² 5.20 mL x (x (—) × (- cm³ = =