705. Compute the reaction R and sketch the shear and moment diagrams for the propped beam shown in Fig. P-705. Ans. R woL/10 use area moment method wo Figure P-705 R.
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- A beam is loaded as shown in FIGURE X.1. Which of the following gives the max. shear? a. 11.57 kNb. 19.23 kNc. 17.86 kNd. 12.48 kN2. Which of the following gives the max. positive moment? a. 11.57 kNb. 19.23 kNc. 17.86 kNd. 12.48 kN3. Which of the following gives the location of max. pos. moment from point B? a. 2.25 mb. 2.75 mc. 2.5 md. 2.35 m5.Calculate the moment at right end of span BC (MBC) in kN.m.0 6.Calculate the shear at left end of span AB in kN.0 7.Calculate the shear at right end of span AB in kN.0 8.Calculate the shear at left end of span BC in kN.0For the frame and loadings shown P=2240 KN, and F=1120 magnitude of verticalreaction at E magnitude of verticalreaction at A magnitude of verticalreaction at C
- Given a shear diagram: 1. Which of the following most nearly gives the location of maximum moment from the left support? a. 1.78 m b. 3.26 m c. 4.23 m d. 6.23 m 2. Which of the following most nearly gives the maximum positive moment? a. 100.00 kN.m b. 83.93 kN.m c. 76.33 kN.m d. 54.32 kN.m 3. Which of the following most nearly gives the location of the point of inflection from the left support? a. 4 m b. 3 m c. 2 m d. 1 mSITUATION 19: A simply supported beam 10m long has a 2m overhang beyond the left support. A highway uniform load of 9.35 kN/m and a concentrated load of 116 kN will pass through this beam.58. Determine the length of the beam over which the uniform load could be placed to produce maximum positive shear at the midspan. a. 3 b. 7 c. 5d. 259. Determine the length of the beam over which the uniform load could be placed to produce maximum negative shear at the midspan. a. 5 b. 7 c. 3 d. 260. Determine the maximum shear at midspan if the concentrated load is placed at the end of the overhang.a. 34.19 kN b. 28.65 kN c. 36.76 kN d. 32.70 kNPart 1a) Calculate the internal normal force (in lb) in section R-R. Indicate directions of internal reaction: L for left; R for right; U for up; D for down; CW for clockwise; CCW for counterclockwise. (Answer profile: 500 CCW)b) Calculate the internal shear force (in lb) in section R-R. Indicate directions of internal reaction: L for left; R for right; U for up; D for down; CW for clockwise; CCW for counterclockwise. (Answer profile: 500 CCW)c)Calculate the internal bending moment (in lb-ft) in section R-R. Indicate directions of internal reaction: L for left; R for right; U for up; D for down; CW for clockwise; CCW for counterclockwise. (Answer profile: 500 CCW)
- Compute for the Beam Reactions and draw the Shear and Moment Diagram of the beam using Moment Distribution Method (MDM) Only. Assume EI = 20000 kNm^2 to compute for FEM Find the relative stiffnessReplace the loading (Figure 1) by an equivalent resultant force and couple moment at point O. Suppose that F1={8i−2k}kN and F2={−4i+5j−2k}kN. Part A Part complete Determine the resultant force. Enter the x, y, and z components of the force in kilonewtons to three significant figures separated by commas. Part B Determine the equivalent resultant couple moment about point O. Enter the x, y, and z components of the moment in kilonewton-meters to three significant figures separated by commas.Determine the maximum ultimate positive and negative moments for the simply supported beam withan overhang under different loading patterns of live load combined with dead load. Also draw the shearand moment diagrams and calculate the location of the point of inflection. WD = 20 KN/m (including selfweight), WL = 30 KN/m.
- Draw the shear and moment diagrams given that Ra=110.2 kN, Rb=310.1 kN, Rc=220.6 kN, Ma=-124.5 kN m, Mb =-258.9 kN m, Mc = -160.5 kNIn the figure on the right where there is a single load of 50 N at point B of the given rod system, (between AB: 4m / BC: 1m) a) Calculate the support reactions? b) Immediately after support A, just before point B and immediately after and just before the C-bracket Find the cross section effects by cutting? c) Draw the cross section effect diagrams?force D=15kips. Find only the reactions