[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the volume proportion of solid copper in a sample, was given by J 6y1(1 – y1) 0< y1 < 1 f1(y1) = elsewhere The density function for Y2, the proportion of type A crystals among the solid copper, was given as (3y 0< y2 <1 f2(४2) = elsewhere The variable U = YY2 gives the proportion of the sample volume due to type A crystals. If Yi and Y, are independent, find the probability density function for U.

Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter1: Functions
Section1.2: Functions Given By Tables
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[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the
volume proportion of solid copper in a sample, was given by
6y1(1 – yı) 0 < y1 <1
f1(y1) =
elsewhere
The density function for Y2, the proportion of type A crystals among the solid copper, was
given as
|3y3 0< y2 < 1
f2(y2) =
0.
elsewhere
The variable U = Y¡Y2 gives the proportion of the sample volume due to type A crystals. If
Y and Y, are independent, find the probability density function for U.
Transcribed Image Text:[8] 3. In a process of sintering(heating) two types of copper powder, the density function for Y1, the volume proportion of solid copper in a sample, was given by 6y1(1 – yı) 0 < y1 <1 f1(y1) = elsewhere The density function for Y2, the proportion of type A crystals among the solid copper, was given as |3y3 0< y2 < 1 f2(y2) = 0. elsewhere The variable U = Y¡Y2 gives the proportion of the sample volume due to type A crystals. If Y and Y, are independent, find the probability density function for U.
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