-8- 7 -6 3 2- 4 5 6 7 -4 -3 -2 -1 0 -1- -8 -7 -6 -5 2 -3 4- -5 -6- -7- --8- 3- 2.

Q: 2-{-7+4[(3-5)2-22

A: Solution  2--7+4[(3-5)2-22] First we will solve inner bracket then outer bracket  Therefore…

Q: X=-3 -y- -5 .4 -3 1 -5 -4 -3 -2 -1 -1 3 4 5 -21 141 -5

A: Given: Graph for line x = -3    The graph of line x =-3  is the vertical line passing through the…

Q: -7 6-5 4-3 -2 2 3 4 5 %24 - ?799ヤ -1 65 3. 今

A:

Q: -2 -2 0 3 4 4 -1 1 -1 | A = |0 -1 3 3 2 -3 4 -7 -2 0 9 -5-

A:

Q: 10 2- -6 -4 -2 -6- -10- to

A:

Q: Ay 5- 4- 3- -3-2-11- 123/4 5 6 78 9 -2- -3+ -4- -5- -6- 中 の寸ウ/G H

A: The ordered pair comprises of the (x-coordinate, y-coordinate). The x-coordinate for the given…

Q: 6- 5 3. 2+ -7-6 5 -4-32 2 3 4 5 6 7 4 -5- -6-

A: Solution of this question is

Q: х2 - 6х + 5 (-) 3x²- 2x – 2 8. Зу? - 2у - 1 | (-) - 5y²- 2y + 6 9. (7а + 6b - 9с) - (За - 6с)

A: To subtract the given polynomials.

Q: 10 8- -7- 9- -5- 1. -3 -2 -8 -6 -5 -4 -3 -2 3. 4. 9.

A:

Q: -10 -8 -6-4 -2 > y 10 8 6 4 2 -2 4 -6 -8 -10 2 4 6 8 10 X

A:

Q: 大 4- -5-4 -3 -2 -1 2 3 4 X -2 -3 -4 -5 -7

A:

Q: 6 4 -3-- 2-- 1 -1 1 2 3 4 8 --1 LO

A: Given that graph of f(x) To find absolute minimum value of funnction

Q: 10 -8- -6- -2 -10 -8 -2 2 4 6. 8 10 -2 --8 -10

A:

Q: 10 -8- -6- -2 -10 -8 -6 -2 6 10 -2- --6- -8 -10 |으

A:

Q: -6 -4 21 6 X -2- -4- X= - 4,

A: Given: The graph of f(x) is

Q: 4. -15 -10 (-4,4) (-4, 3) -5 (-4,-5) -4,-6) -10- 0 -5- --10- --15- 5

A: The standard form of the equation of hyperbola with center (h, k) and transverse axis parallel to…

Q: - 10- 8 7- 5- 4- 3 2- 1- -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 1 2 3 4 5 6 7 8 9 10 -1- --2- --3 --4- -5…

A:

Q: - 2 2 - 4 17) - 3 ; 8, 2 - 2 4 3 Ans. 4, ;-4, s0, 2 2 -4 1 2 - 6 4

A:

Q: -7 3 -10 -9 -8 -7 -6 -5 -4 -2 5 6. 8. 10 -7 9. 7. 3. 2. 1, 2.

A:

Q: 10 -8- -6- -2 -10 -8 -6 -2 6 8 10 -2 --6-

A:

Q: -10 -9 -8 -7 -6 -4 -3 -2 -11 1 4 5. 10 00 6. %2. 2. 3. 2. 1. 2. 5.

A: Find two points on line then find equation of line by standard form of line

Q: 8 7- 1. -7 -6 -5 -4 -3 -2 -1 0 6 7. 8 9 10 11 -1 A -2- -3 4. 3. 2. 4. 3. 2.

A: There are many possibilities for the forth point in the first quadrant The simplest case is drawing…

Q: (-8-2.) -(-3-2) 1 8-2х %3D 1/3

A: Given:         -8-2x13=-3-x13

Q: -10 -9 -8 -7 -6 -5 -4 -3 -2 -1. 2. 3 5. 6. 8 9 10 -5 -7 00 1. 7. 2. 6.

A: The graph of line is shown in the figure.

Q: 2- .....*. -5 -4 -3 -2 A (-2, 2) C (2, -2) В (4, 3) D (-4, 0)

A: From above shaded region it is clear that

Q: -13 -12 -11 -10 -9 -8 -4 -3 -2 - 10 %24

A:

Q: Ay 16- 12- 8- -16-12 -8 -4 -4- 16 12 -8- -12- -16- 4-

A: Took 2 coordinates on the graph ; (4, 0) and (5, 8)  The equation of the straight line written as  y…

Q: What is the standard form of the equation of the circle?

A: Center of the circle is =(h,k)= (2,-8) Radius of the circle = r = 1

Q: find rref 2 6 -4 0 1 2 -3 6 8 3 2 5

A: NOTE: Refresh your page if you can't see any equations. . the given matrix is now convert into…

Q: 5- 4- 3 2- -14 -13 -12 -11 Д0 -9 -8 -7 -6 -5 -3 -2 -1 -- 7 8 9 Q 11 12 13 14 2 3 6 -2 -3- -5-

A:

Q: -3 -3 2 -5 9 -3 -2 2 = 4X – 3 8 - -7 -8

A:

Q: `-10 -9 -8 -7 -3 -2 -1 1 2 3, 4 5 6 7 8 9 10 -1 -2 -3 -6 -7 -8 -9 -10

A:

Q: which one is y=g(x), y =g'(x), y=g''(x), y=g'''(x)

A: We have to fund which graph corresponds to g(x),g'(x),g''(x),g'''(x)

Q: -4 -3 -ス - 1 -2 Undefined 2 6 -5 -4 -3 -2

A:

Q: 3 由 -9-8-7--5-4-3-2-1 1 2 345 6 -1 -2 7 8 9 -3 -4 -5

A: We have to find the discontinuous points.

Q: -1 -3 -1 1 -2 4 -3 1 1 3 2 3.) -2 4 -3 -4 2 0 -4 2 0 4 1 -1

A:

Q: 10- -10 -8 -6 -2 10

A: The requirement of the question is to find the local extrema from the graph. Local extrema exists on…

Q: (-5) + 4 – 1+ 4- (-21) * (-7)) ova

A: Simplification

Q: 5+ -5 -4-3 2 -1 2 3 4 5 -2 -3- -4 -5+ 3.

A:

Q: 4- 3. -5 -4 -3 -2 -1 4 -2 -3 -4 - -5- 3. 2.

A:

Q: |2y + 6| < 10 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10

A: Given:2y+6&lt;10

Q: (1, -1) 4 5 6 7 8 9 10 11 12 -12-11-10 -9 -8 - -6 -5 -4 -3 -2 -1, (-3, -2). -2 -3 -4 -5

A:

Q: 10- 8- 6- 4- 2- -8 -4 -2 10 2- 4- -6- 40

A: Draw a graph.

Q: 7- 4- 2 -8 -7 -6 -5 -4 -3 -2 -1 I 2 5 6 7 -2 -3 -4 -5 -7 6

A: here equation is given  by y=4ax^2 vertex at (3,-1) than  x=a(y-3)^2-1 now x intercept is (5,0) that…

Q: -5 -4 -3 -2 -1 F-1 2 3 /4 5 -2 -3 -4 -5

A:

Q: -2 -1 -6 -5- -4 --3- -2 1 0 -2 1 3 4 - 5 6

A: we can see which one is correct by going y= log x to given graph

Q: -4 -3 -2 –1 0 -10 1 2 3 4 $ -2

A: