8 An energy cycle is drawn for the following reaction. Br₂(1) + 3F₂(g) → 2BrF3(1) +698kJ 2Br(g) + 6F(g) 2BrF3(g) 2BrF3(1) Br₂(l) + 3F₂(g) The standard enthalpy of formation of BrF3(1) = -301 kJ mol-¹. The enthalpy change of BrF3(1) to BrF³(g) is +44 kJ mol¯¹. What is the average bond energy of the Br-F bond in BrF3? 152 kJ mol-¹ B 202 kJ mol-¹ C 304 kJ mol-¹ A D 404 kJ mol-¹
Types of Chemical Bonds
The attractive force which has the ability of holding various constituent elements like atoms, ions, molecules, etc. together in different chemical species is termed as a chemical bond. Chemical compounds are dependent on the strength of chemical bonds between its constituents. Stronger the chemical bond, more will be the stability in the chemical compounds. Hence, it can be said that bonding defines the stability of chemical compounds.
Polarizability In Organic Chemistry
Polarizability refers to the ability of an atom/molecule to distort the electron cloud of neighboring species towards itself and the process of distortion of electron cloud is known as polarization.
Coordinate Covalent Bonds
A coordinate covalent bond is also known as a dative bond, which is a type of covalent bond. It is formed between two atoms, where the two electrons required to form the bond come from the same atom resulting in a semi-polar bond. The study of coordinate covalent bond or dative bond is important to know about the special type of bonding that leads to different properties. Since covalent compounds are non-polar whereas coordinate bonds results always in polar compounds due to charge separation.
Step by step
Solved in 3 steps with 40 images
