8. 4. Using the tangent to the curve (shown as the orange line in the figure), what is the instantaneous velocity of the particle at t = 1.50 s? (Express your answer in vector form.) %3D y (m) (0,2) (3,20) 20 16 W-2 yf -Yü = 3-0 %3D 12 18 4 0. +(s) a =6 4 a ? (A. 6j mis B. 6 i m/s C. -1/3 î m/s D. 3 j m/s E. 1j
8. 4. Using the tangent to the curve (shown as the orange line in the figure), what is the instantaneous velocity of the particle at t = 1.50 s? (Express your answer in vector form.) %3D y (m) (0,2) (3,20) 20 16 W-2 yf -Yü = 3-0 %3D 12 18 4 0. +(s) a =6 4 a ? (A. 6j mis B. 6 i m/s C. -1/3 î m/s D. 3 j m/s E. 1j
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Transcribed Image Text:41
Duni OLURO ani OLS O't sa NPI PU
ball assuming the ball is hit at the ground level. Use g = 10 m/s2. Hints: first find the initial velocity
of the ball.
A. 20 m.
B. 40 m
C. 10 m
D. 5 m
E. 60 m
4. Using the tangent to the curve (shown as the orange line in the figure), what is the
instantaneous velocity of the particle at t = 1.50 s? (Express your answer in vector form.)
y (m)
(0,2) (3,20)
20
16
W-2
12
3-0
18
3
%3D
4
-t (s)
2
3.
a
A. 6 j m/s
B. 6 i m/s
C. -1/3 i m/s
D. 3j m/s
E. 1j m/
5. A particle's position is given by x(t) = (12 + 3t + t2) i m for time t in seconds. Find the
particle's velocity at time t = 5 s.
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