8. Calculate the heat required to convert 5,5 g of ice at -25°C to steam at 118°C. 9=mcST onoH q=(5.5g)(2.0951g.oun) (o-(-25)°C) -287.37S J bebivo Hfus mol HzO +118°C 100 5.5g H20)=1,836KJ=\836J 18.0gimal =(6.0115)mol) q=mcAT 25°C q =C5.5g) (4.1831g.n)(lo0-0°c) = 2299 J q=Huap, mmol 4: (40,67nimai) tizO 18,0gima J=12427 J )= 12.427 h q=MCAT 4=Cs.Sg)(1.84 31g.6)Cl18-100°C)-182.16 J 1743 287.3755+18365+2299st124275182.16J=170313= phasiom erioslea nfog grilad arigit.er asri Jbloeo

Chemistry: An Atoms First Approach
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Chapter9: Liquids And Solids
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Problem 99E: What quantity of energy does it take to convert 0.500 kg ice at 20.C to steam at 250.C? Specific...
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8.
Calculate the heat required to convert 5,5 g of ice at -25°C to steam at 118°C.
9=mcST
onoH
q=(5.5g)(2.0951g.oun) (o-(-25)°C) -287.37S J
bebivo Hfus mol HzO
+118°C
100
5.5g H20)=1,836KJ=\836J
18.0gimal
=(6.0115)mol)
q=mcAT
25°C
q =C5.5g) (4.1831g.n)(lo0-0°c) = 2299 J
q=Huap, mmol
4: (40,67nimai) tizO
18,0gima
J=12427 J
)= 12.427 h
q=MCAT
4=Cs.Sg)(1.84 31g.6)Cl18-100°C)-182.16 J
1743
287.3755+18365+2299st124275182.16J=170313=
phasiom erioslea
nfog grilad arigit.er asri Jbloeo
Transcribed Image Text:8. Calculate the heat required to convert 5,5 g of ice at -25°C to steam at 118°C. 9=mcST onoH q=(5.5g)(2.0951g.oun) (o-(-25)°C) -287.37S J bebivo Hfus mol HzO +118°C 100 5.5g H20)=1,836KJ=\836J 18.0gimal =(6.0115)mol) q=mcAT 25°C q =C5.5g) (4.1831g.n)(lo0-0°c) = 2299 J q=Huap, mmol 4: (40,67nimai) tizO 18,0gima J=12427 J )= 12.427 h q=MCAT 4=Cs.Sg)(1.84 31g.6)Cl18-100°C)-182.16 J 1743 287.3755+18365+2299st124275182.16J=170313= phasiom erioslea nfog grilad arigit.er asri Jbloeo
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