8. The channel used to carry traffic from the mobile user to a base station Mark only one oval. FDD RVC GSM GPRS 000
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- Please answer the following task using WireShark. Please also include screenshot images. View Image attached! Examine the frame contents for one of the selected packets by expanding the frame, Ethernet andother details in the lower part of the screen. Explain the encapsulation at the different protocol layers that you can observe. How large is the frame?Against each point write the appropriate IoT protocol type. 1. Bluetooth 2. Connect low power IoT devices 3. Datalink/physical layers 4. Point-to-point communication 5. Connect devices over the network 6. End-to-end data communication 7. Presentation/application layers 8. MQTTThe 2G cellular system GSM 900 operates its 125 forward channels in the uplink frequency band 890.2-915 MHz and 125 reverse channels in the frequency band 935.2-960 MHz. Each channel has a bandwidth of 200 kHz. i. What is the bandwidth in the forward channels (uplink frequency band) and reverse channels (downlink frequency band)? ii. If each channel is subdivided into 16 time slots, what is the sub channel spacing? If each channel is shared by 16 users then compute the total number of users per cell?
- Which transmission mode should be used to send information from a single point to another point?a.multicast b.unicast c.broadcast d.anycastOf the following code that you would modify to include the demodulated signal available in quadrature, in order to make the receiver immune to the lack of synchronization.the complete code is in https://www.onlinegdb.com/I_CHQZUVa# Filtered demodulated channelss:x_re = signal.lfilter(b_lp, 1, y_re)X_re = np.fft.fft(x_re)x_im = signal.lfilter(b_lp, 1, y_im)X_im = np.fft.fft(x_im)#Saturation:y_s=saturate(x_re)Dear Writer this is my calculation solution.could you please double check it and let me know it if it soccrect or should i proceed with your solution: Please provide justification if correction is need and correct answer.Thank you in advance. a) The transmission time of a frame can be calculated as follows: Propagation delay (Tp) = distance/speed = 5km / 200000 km/s = 0.0025ms Transmission time (Tt) = frame size/bandwidth = 10000 * 8bits / (1Mbps * 10 ^ 6) = 0.008sec = 8ms Total time for transmission = 2 * Tp + Tt(since the frame has to travel from A to D and then D to A) = 2 * 0.0025ms + 8ms = 0.005ms + 8ms = 8.005ms The transmission time of the frame from A to D is 8.005 ms. b) The efficiency of the CSMA/CD protocol is given by the formula: Tt is the transmission time of a frame C is the number of collisions, Tp is the propagation time of a signal from one end of the segment to the other. Efficiency = Tt / (C * 2 * Tp + Tt + Tp) Assuming that there are no other…
- 93. A __________ forwards every frame; it has no filtering capability. a. passive hub b. repeater c. bridge d. routerPlease give a neat and understandable configuration. Thanks. Assume there are 4 voice channels, each occupying a bandwidthof 40 kHz. These 4 voice channels need to be combined into a link with a minimum bandwidth of175 kHz, from 131kHz to 306 kHz. There are guard bands of 5 kHz between the channels to preventinterference. Show the configuration using the frequency domain121. Which of the following statement is correct? a. Satellite transponders contain a device that echos the radiation without change from one point on earth to another b. Satellite transponders contain a receiver and transmitter designed to relay microwave transmissions from one point on earth to another c. Satellite transponders use lower frequency reception of radiation from earth stations and higher frequency for transmission to earth stations d. Satellite transponder contains devices that transform the message sent from one location on earth to a different code for transmission to another location
- Which statement is true about Symmetric (single-line) digital subscriber line (SDSL) a. A technology based on DSL; allows different data rates depending on the type of communication; differing rates may also assigned tosubcribers based on their demand on bandwidth b. A communication technology in which the downloadstream data rate is higher than theupstream rate c. Same as HDSL but one uses single pair twisted cable, available to mostresidential subscriber to achieve the same data rate as HDSL d. Design byTelcordia as an alternative to the T-1 lineIf you had to download a 12 MByte narrated PowerPoint from your instructor, approximately how long would it take to transfer using each of the following circuits? Assume that control characters add 10% to the message. Dial up modem at 33.6 Kbps Cable modem at 1.5 Mbps Cable modem at 1.5 Mbps with V.44 data compression at a 6:1 ratio DSL modem at 6 MbpsWhen forwarding a frame to its destination, do the following devices (i) hub (ii) Bridge and (iii) switch require to use the CSMA/CD protocol? Explain!