How do I solve question 8???? e.3.9 m/s up the incline208.In the figure, if F= 2.0 N and M = 1.0 kg, what is the tension in the connecting string? Thepulley and all surfaces are frictionless.Newton's Second Lau i Famam: IkqF-T 2MaFT=2Ma ~ for black 2mET-Mysin@=Ma - for block2Mineline T:1(4.8) sinsoT: 4.9 aonsubshitute 2 im I2-2a.9.8sin 30 a2-9.8sin 30 3a2- 4.9 3aa.2.6 Na : -.967 mls*b.1.1 NTensian mgal Tiasion : mlgra);at fension migra)с.2.1 Nd.1.6 Nе.3.7 N

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Description: How do I solve question 8???? e.3.9 m/s up the incline208.In the figure, if F= 2.0 N and M = 1.0 kg, what is the tension in the connecting string? Thepulley and all surfaces are frictionless.Newton's Second Lau i Famam: IkqF-T 2MaFT=2Ma ~ for black 2

In equilibrium, Fext = Ma Mg Sin 30° - T = Ma -------(1) T + F = 2 Ma -------(2) From eq 1 &…

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8.In the figure, if F= 2.0 N and M = 1.0 kg, what is the tension in the connecting string? The %3D pulley and all surfaces are frictionless. Newton's Second Lawi f=ma F-T 2Ma f-T: 2Ma T-Mysin@=Ma ~ for block on ineline T:1(4) sindo M: lkq 2M for block 2m T: 4.9a subshitute 2 in I 2-2a.9.8sin 30 = a 2-9.8 sin 30 3a 30° 2- 4.9 3a 2.6 N a: -.967 mls b. 1.1 N Tension mg: al Tintion = mlgea);af fensionmígra) c. 2.1 N d. 1.6 N е. 3.7 N

8.In the figure, if F= 2.0 N and M = 1.0 kg, what is the tension in the connecting string? The %3D pulley and all surfaces are frictionless. Newton's Second Lawi f=ma F-T 2Ma f-T: 2Ma T-Mysin@=Ma ~ for block on ineline T:1(4) sindo M: lkq 2M for block 2m T: 4.9a subshitute 2 in I 2-2a.9.8sin 30 = a 2-9.8 sin 30 3a 30° 2- 4.9 3a 2.6 N a: -.967 mls b. 1.1 N Tension mg: al Tintion = mlgea);af fensionmígra) c. 2.1 N d. 1.6 N е. 3.7 N

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter4: The Laws Of Motion

Section: Chapter Questions

Problem 39P

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