9 10 11 12 13 14 15 16 17 18 19 20 x:integer procedure setx (n:integer) x :=n end procedure printx() print (x) end procedure first() setx (1) printx() end procedure second() end x:integer setx (2) printx() 21 22 setx (0) 23 first() printx() 24 second() printx() What does this program print if the language uses static scoping? What does it print with dynamic scoping? Why?
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- #The Iris Dataset import sklearn.datasetsimport matplotlib.pyplot as plt import numpy as np import scipy iris = sklearn.datasets.load_iris() Write a function that takes in an index i and prints out a verbose desciption of the species and measurements for data point i. For example:Data point 5 is of the species setosaIts sepal length (cm) is 5.4Its sepal width (cm) is 3.9Its petal length (cm) is 1.7Its petal width (cm) is 0.4A fibonacci series is defined as a series where the number at the current index, is the value of the summation of the index preceding it (index -1) and (index-2). Essentially, for a list fibonacci_numbers which is the fibonacci numbers series, fibonacci_numbers[i] = fibonacci_numbers[i-1] + fibonacci_numbers[i-2] The fibonacci series always begins with 0, and then a 1 follows. So an example for fibonacci series up to the first 7 values would be - 0, 1, 1, 2, 3, 5, 8, 13 Complete the fibonacci(n) function, which takes in an index, n, and returns the nth value in the sequence. Any negative index values should return -1. Ex: If the input is: 7 the output is: fibonacci(7) is 13 Important Note Use recursion and DO NOT use any loops. Review the Week 9 class recording to see a variation of this solution. def fibonacci(n): if (n < 0 ): return -1 else: return n fibonacci_numbers = (fibonacci[n - 1] + fibonacci[n - 2]) return fibonacci_numbers(n) # TODO: Write…Can you fix the code please on the first picture shows the error output. // Corrected code #define _CRT_SECURE_NO_WARNINGS #include "LibraryManagement.h" #include "Books.h" #include "DigitalMedia.h" #include "LibraryConfig.h" #include #include #include #include // Include the necessary header for boolean data type // Comparison function for qsort to sort Digital Media by ID int compareDigitalMedia(const void* a, const void* b) { return ((struct DigitalMedia*)a)->id - ((struct DigitalMedia*)b)->id; } // initializing library struct Library initializeLibrary() { struct Library lib; lib.bookCount = 0; lib.ebookCount = 0; lib.digitalMediaCount = 0; // Initialize book array for (int i = 0; i < MAX_BOOK_COUNT; i++) { lib.books[i].commonAttributes.id = -1; // Set an invalid ID to mark empty slot } // Initialize ebook array for (int i = 0; i < MAX_EBOOK_COUNT; i++) { lib.ebooks[i].commonAttributes.id = -1; }…
- Given an array of strings strs, group the anagrams together. You can return the answer in any order. An Anagram is a word or phrase formed by rearranging the letters of a different word or phrase, typically using all the original letters exactly once. Example 1: Input: strs = ["eat","tea","tan","ate","nat","bat"] Output: [["bat"],["nat","tan"],["ate","eat","tea"]] Example 2: Input: strs = [""] Output: [[""]] Example 3: Input: strs = ["a"] Output: [["a"]] Constraints: 1 <= strs.length <= 104 0 <= strs[i].length <= 100 strs[i] consists of lowercase English letters.Given subsets A and B of a universal set with 10 elements {0, 1, 2, 3, 4, 5, 6, 7, 8,9}. Write a C++ or Java program that uses bit strings to find A È B, A Ç B, and A – B. Print tothe screen set A, set B ( be sure to print out the name of the sets), as well as the set operation results(be sure to print out the name of the operations).The program requires that elements of subsets A and B are from user input. You can make theassumption that user input numbers are within the domain of the set {0, 1, 2, ..., 9} and there isno improper input.Additional requirements and reminders:• The use of STL, templates, and operator overloading is not permitted in any form.• Remember: You must use a bit string when representing a set. You may not use an array ofBoolean variables.• The elements of subset A and subset B must from user input. You may not hardcode the twosubsets in your program.Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.length - 1. import java.util.Scanner; public class CourseGradePrinter {public static void main (String [ ] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int [ ] courseGrades = new int[NUM_VALS];int i; for (i = 0; i < courseGrades.length; ++i) {courseGrades[i] = scnr.nextInt();} /* Your solution goes here */ }}
- Write a Java program using methods and arrays. Create “HW9_lastname.java” program that: Prints a program title Creates a table with grades for our class students and initializes grades with random values Finds the largest grade for every student Displays the following information: Student name: CIS 232 Introduction to Programming Programming Project 9 Due Date: November 9, 2020 Instructor: Dr. Lomako ASSIGNMENT GRADES HW1 HW2 NW3 HW4 HW5 HW6 HW7 Student Name _______________________________________________________ 0001 0076 0078 0068 0003 0012 0048 Adams 0033 0042 0035 0020 0021 0058 0060 Aimuengheuwa 0013 0021 0037 0099 0025 0098 0060 Bennett 0068 0089 0007 0051 0083 0057 0080 Bowen 0062 0078 0083 0013 0023 0043 0098 Brown 0052 0003 0033 0091 0003 0031 0080…Integer numSize is read from input. ArrayList colorsList contains numSize strings read from input. Complete the enhanced for loop to output each value in colorsList. Ex: If the input is: 5 blue red violet green orange then the output is: blue is available red is available violet is available green is available orange is available import java.util.Scanner;import java.util.ArrayList; public class Colors { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); ArrayList<String> colorsList = new ArrayList<String>(); int numSize; int i; numSize = scnr.nextInt(); for (i = 0; i < numSize; ++i) { colorsList.add(scnr.next()); } for (/* Your code goes here */) { System.out.println(colorVal + " is available"); } }} java pleaseRetrieving a value using its associated key can be accomplished using anindexer, which works just like an indexer for an array. A key is passed in asthe index value, and the value associated with the key is returned, unless thekey doesn’t exist, in which a null is returned.Write short code segment demonstrates how this technique works:
- Define a collection “ArrayList” to store the students' names. Use a loop to take 5 students’ names from the user and store them in the collection. Add two student names to the collection and remove the last name in the list. Insert a student name in third place in the collection. Sort the names alphabetically. Ask the user to enter a student name and search for it in the collection and prints the result as “Found” or “Not Found”. Print the whole collection using the enhanced for loop. (java)For any element in keysList with a value smaller than 50, print the corresponding value in itemsList, followed by a space. Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 10 40 import java.util.Scanner; public class Compare { public static void main(String args[]) { final int SIZE_LIST = 4; int[] keysList = new int[SIZE_LIST]; int[] itemsList = new int[SIZE_LIST]; int i; Scanner input = new Scanner(System.in); keysList[0] = input.nextInt(); keysList[1] = input.nextInt(); keysList[2] = input.nextInt(); keysList[3] = input.nextInt(); itemsList[0] = input.nextInt(); itemsList[1] = input.nextInt(); itemsList[2] = input.nextInt(); itemsList[3] = input.nextInt(); //answer// System.out.println(); } }IntSet unionWith(const IntSet& otherIntSet) const; //Unions the current set with the passed set. IntSet::unionWith(const IntSet& otherIntSet){ for (int i = 0; i < otherIntSet.used; ++i) //For each element in the passed set. { add(otherIntSet.data[i]); //Add it to current set. }}