Integer numSize is read from input. ArrayList colorsList contains numSize strings read from input. Complete the enhanced for loop to output each value in colorsList. Ex: If the input is: 5 blue red violet green orange then the output is: blue is available red is available violet is available green is available orange is available import java.util.Scanner;import java.util.ArrayList; public class Colors { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); ArrayList<String> colorsList = new ArrayList<String>(); int numSize; int i; numSize = scnr.nextInt(); for (i = 0; i < numSize; ++i) { colorsList.add(scnr.next()); } for (/* Your code goes here */) { System.out.println(colorVal + " is available"); } }} java please

Integer numSize is read from input. ArrayList colorsList contains numSize strings read from input. Complete the enhanced for loop to output each value in colorsList. Ex: If the input is: 5 blue red violet green orange then the output is: blue is available red is available violet is available green is available orange is available import java.util.Scanner;import java.util.ArrayList; public class Colors { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); ArrayList<String> colorsList = new ArrayList<String>(); int numSize; int i; numSize = scnr.nextInt(); for (i = 0; i < numSize; ++i) { colorsList.add(scnr.next()); } for (/* Your code goes here */) { System.out.println(colorVal + " is available"); } }} java please

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter9: Advanced Array Concepts

Section: Chapter Questions

Problem 19RQ

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Write a for loop to print all elements in courseGrades, following each element with a space (including the last). Print forwards, then backwards. End each loop with a newline. Ex: If courseGrades = {7, 9, 11, 10}, print: 7 9 11 10 10 11 9 7 import java.util.Scanner; public class CourseGradePrinter {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int [] courseGrades = new int[NUM_VALS];int i; for (i = 0; i < courseGrades.length; ++i) {courseGrades[i] = scnr.nextInt();} /* Your solution goes here */ P.S. The answer came out wrong the first try 7 9 11 10 10 11 9 7Enter
*in java* Write a for loop to print all NUM_VALS elements of array hourlyTemp. Separate elements with a comma and space. Ex: If hourlyTemp = {90, 92, 94, 95}, print:90, 92, 94, 95 Your code's output should end with the last element, without a subsequent comma, space, or newline. import java.util.Scanner; public class PrintWithComma {public static void main (String [] args) {Scanner scnr = new Scanner(System.in);final int NUM_VALS = 4;int[] hourlyTemp = new int[NUM_VALS];int i; for (i = 0; i < hourlyTemp.length; ++i) {hourlyTemp[i] = scnr.nextInt();} /* Your solution goes here */ System.out.println("");}}
Write a for loop to initialize the objects in the ArrayList created in question number 2 above to -1. import java.util.*; public class test { public static void main(String[] args) { int n = 25; ArrayList<Integer> list = new ArrayList<Integer>(n); for(int i = 0;i<n;i++){ list.add(-1); } for(int i = 0;i<n;i++){ System.out.print(list.get(i) + " "); } } } Write Java statements to add the integers 1001, 1100, and 1110 to the resulting ArrayList .
Define a collection “ArrayList” to store the students' names. Use a loop to take 5 students’ names from the user and store them in the collection. Add two student names to the collection and remove the last name in the list. Insert a student name in third place in the collection. Sort the names alphabetically. Ask the user to enter a student name and search for it in the collection and prints the result as “Found” or “Not Found”. Print the whole collection using the enhanced for loop. (java)
write a program that reads the students.txt file and stores the name of the student and the grade information as a student object in an arraylist sorts the students names based on their first grade in decreasing order using the selection sort algorithm writes the sorted list as the students last name , middle name (if theres one), first name , and grade information into a text file output example: Robison, Lee 95 80 Green, Alex R 85 60 Waston, Zoe G 100 80 use java
THE QUESTION IS ATTACHED: PLEASE AVOID USING import java.util.ArrayList; import java.util.HashMap; import java.util.Map; BECAUSE I HAVEN'T STUDIED THEM YET, YOU CAN USE 1D AND 2D ARRAYS. YOU ARE FREE TO USE import java.io.File; import java.io.FileNotFoundException; import java.io.FileWriter; import java.io.IOException; EFFECTIVELY USE LOOPS AND CONTROL STATEMENTS. ALSO TRY AND CATCH. TXT. FILE IS INCLUDED BELOW: MOVIE NAME, MOVIE YEAR, RATING AND GENRE. The Martian2015Adventure8.0Murder on the Orient Express2017Crime6.5X-Men: First Class2011Action7.7X-Men: Days of Future Past2014Action7.9This Means War2012Action6.3Godzilla vs. Kong2021Adventure6.5Black Widow2021Action7.5Zack Snyder's Justice League2021Action8.1The Ten Commandments1956Drama7.9The Father2020Drama8.3Nobody2021Crime7.5Promising Young Woman2020Crime7.5What Lies Below2020Horror4.4Shrine2021Horror5.1Bram Stoker's Dracula1992Horror7.4
For any element in keysList with a value greater than 40, print the corresponding value in itemsList, followed by a semicolon (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20;30; import java.util.Scanner; public class Compare { public static void main(String args[]) {final int SIZE_LIST = 4;int[] keysList = new int[SIZE_LIST];int[] itemsList = new int[SIZE_LIST];int i;Scanner input = new Scanner(System.in); keysList[0] = input.nextInt();keysList[1] = input.nextInt();keysList[2] = input.nextInt();keysList[3] = input.nextInt(); itemsList[0] = input.nextInt();itemsList[1] = input.nextInt();itemsList[2] = input.nextInt();itemsList[3] = input.nextInt(); /* Your code goes here */ System.out.println();} }
Write a method that removes adjacent duplicates from an array list. Complete this code. import java.util.ArrayList; public class ArrayListUtil{/**Removes adjacent duplicates from an array list of strings.@param word an array list of strings*/public static void removeAdjacentDuplicates(ArrayList<String> words){. . .}}
The printRightToLeft method is intended to print the elements in the ArrayList words in reverse order. For example, if words contains ["jelly bean", "jukebox", "jewelry"], the method should produce the following output. jewelry jukebox jelly bean The method is shown below. public static void printRightToLeft(ArrayList<String> words) { if (words.size() > 0) { System.out.println(words.get(words.size() - 1)); /* missing code */ } } Which of the following can be used to replace /* missing code */ so that the printRightToLeft method works as intended? words.remove(0); printRightToLeft(words); words.remove(0); printRightToLeft(words); words.remove(words.size()); printRightToLeft(words); words.remove(words.size()); printRightToLeft(words); words.remove(words.size() - 1); printRightToLeft(words); words.remove(words.size() - 1); printRightToLeft(words); printRightToLeft(words); words.remove(0); printRightToLeft(words); words.remove(0);…
In java, Implement a method that removes all duplicates. Keep the first instance of the element but remove all subsequent duplicate elements.public void removeDuplicates() see the picture for the right output. Given files: Demo6.java public class Demo6 { public static void main(String[] args) { MyLinkedList<String> list = new MyLinkedList<>(); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); TestBench.addToList(list); for (int x = 0; x < list.size(); x += 1 + x/3) { System.out.println("Removing element at index: " + x); list.remove(x); } System.out.println("Result"); System.out.println(list); System.out.println("Shuffling"); list.shuffle(7777); System.out.println(list); System.out.println("Removing duplicates (keeping first instance)"); list.removeDuplicates(); System.out.println(list); }} TestBench.java import java.util.AbstractList; public class TestBench { public static…
THE QUESTION IS ATTACHED: PLEASE AVOID USING import java.util.ArrayList; import java.util.HashMap; import java.util.Map; BECAUSE I HAVEN'T STUDIED THEM YET, YOU CAN USE 1D AND 2D ARRAYS. YOU ARE FREE TO USE import java.io.File; import java.io.FileNotFoundException; import java.io.FileWriter; import java.io.IOException; EFFECTIVELY USE LOOPS AND CONTROL STATEMENTS. TXT. FILE IS INCLUDED BELOW: MOVIE NAME, MOVIE YEAR, RATING AND GENRE. The Martian2015Adventure8.0Murder on the Orient Express2017Crime6.5X-Men: First Class2011Action7.7X-Men: Days of Future Past2014Action7.9This Means War2012Action6.3Godzilla vs. Kong2021Adventure6.5Black Widow2021Action7.5Zack Snyder's Justice League2021Action8.1The Ten Commandments1956Drama7.9The Father2020Drama8.3Nobody2021Crime7.5Promising Young Woman2020Crime7.5What Lies Below2020Horror4.4Shrine2021Horror5.1Bram Stoker's Dracula1992Horror7.4
import java.util.ArrayList; class Rack { privateArrayList<Tile>tiles; publicRack() { tiles=newArrayList<Tile>(); } publicvoidaddTile(Tilet) { tiles.add(t); } /* DO NOT CHANGE THE ABOVE CODE. YOUR JOB IS TO ADD THE FOLLOWING METHODS: .toString() .sortHighToLow() You may also add any helper methods you want, such as swapValues. Note that we want to sort Tiles from highest value to lowest */