9-12 Use the Midpoint Rule with the given value of n to approximate the integral. Round the answer to four decimal places. 9. * sin √x dx, n = 4 Jo 11. 2 X So Jo x + 1 17. lim n→∞ n 17-20 Express the limit as a definite integral on the given interval. n 20. lim n10 i=1 n - dx, i=1 sin Xi 18. lim x√√1 + n10 n n=5 1 + Xi · Δ.x, [0, π] 19. lim [5(x*)³ − 4x*] n→∞ x² Ax, + x³ Ax, [2, 5] 10. f' √x³ + 1 dx, 12. f″ x sin²x dx, n = 4 Ax, 4x] Ax, [2, 7] i=1 (x²*)² + 4 + 1 dx, n = 5 · Δ.x, [1, 3]

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3. 9-12 Use the Midpoint Rule with the given value of n to
approximate the integral. Round the answer to four decimal
places.
9. fsin√xdx, n = 4
11.
2
X
Jo x + 1
17. lim
n→∞
17-20 Express the limit as a definite integral on the given
interval.
n sin Xi
1 + Xi
n
20. lim
n→∞
n
dx, n = 5
18. lim Σx;√√1 + x²³ Ax, [2,5]
n→∞ i=1
i=1
n
Δ.x, [0, π]
19. lim [5(x)³ - 4x*] Ax, [2,7]
n→∞
i=1
1
10. f¹ √√x³ + 1 dx, n = 5
12. fx sin²x dx,
x*
(x*)² + 4
n = = 4
Ax, [1,3]
Transcribed Image Text:3. 9-12 Use the Midpoint Rule with the given value of n to approximate the integral. Round the answer to four decimal places. 9. fsin√xdx, n = 4 11. 2 X Jo x + 1 17. lim n→∞ 17-20 Express the limit as a definite integral on the given interval. n sin Xi 1 + Xi n 20. lim n→∞ n dx, n = 5 18. lim Σx;√√1 + x²³ Ax, [2,5] n→∞ i=1 i=1 n Δ.x, [0, π] 19. lim [5(x)³ - 4x*] Ax, [2,7] n→∞ i=1 1 10. f¹ √√x³ + 1 dx, n = 5 12. fx sin²x dx, x* (x*)² + 4 n = = 4 Ax, [1,3]
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