9 A lion is watching a zebra from 35 m behind it. Both are stationary. The lion then starts chasing by accelerating at a constant rate of 3ms-2 for 5 s. Once at top speed the lion decelerates at 0.5 ms-2. The zebra starts moving 1s after the lion started, accelerating at a constant rate of 2 ms2 for 7s before maintaining a constant speed. a Show that the lion has not caught the zebra after 8s.
A lion is watching a zebra from 35m behind it. Both are stationary. The lion then starts chasing by accelerating at a constant rate of 3m/s^2 for 5s. Once at the top speed the lion decelerates at 0.5m/s^2. The zebra starts moving 1s later after the lion started, accelerating at a constant rate of 2m/s^2 for 7s before maintaining a constant speed. a) show that the lion has not caught the zebra after 8s. b) show that the gap between them at time ts, for t>8, after the start of the lion's motion is given by 0.25t^2-5t+51/2, and hence, determine when the lion catches the zebra or when the lion gets closest and how close it gets.
PLEASE SOLVE BOTH PARTS ( A and B) AND BY USING SUVAT IN A CLEAR STEP BY STEP PROCEDURE
Thanks in advance :)
Trending now
This is a popular solution!
Step by step
Solved in 3 steps