A parallel plate capacitor has plate area 250 cm2 and plate separation distance 5 cm. The charge on the capacitor is shown as 9 nanoCoulombs. (+9 nC on one plate and -9 nC onthe other). A path is shown from point "a" to "b" with the displacement 1.5 cm to the left and 2 cm up. Calculate the change in potential from point "a" to point "b". Answer involts.q = 9 nCq = -9 nCb2.0 cma1.5 cm

Answered: 9 пC q = -9 nC b 2.0 cm

Science

Physics

9 пC q = -9 nC b 2.0 cm

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter16: Electrical Energy And Capacitance

Section: Chapter Questions

Problem 6CQ: An air-filled parallel-plate capacitor with capacitance C0 stores charge Q on plates separated by...

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