9. An electron moves in a circular path perpendicular to a constant magnetic field of magnitude 5.0 mT. The angular momentum of the electron about the center of the circle is 6.00 x 10 J-s. The mass of the electron is 9.1 x 10 kg and its charge is 1.6 x 10-19 C. Determine a) the radius of the path B= 5.0 Fs mg -25 mom- mg = ILXB M = 9.1 X10 3:2.973 X10 IB b) The speed of the electron

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Chapter19: Magnetism
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Problem 66AP: An electron moves in a circular path perpendicular to a constant magnetic field of magnitude 1.00...
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9. An electron moves in a circular path perpendicular to a constant magnetic field of
magnitude 5.0 mT. The angular momentum of the electron about the center of the
circle is 6.00 x 1025 J-s. The mass of the electron is 9.1 x 10 kg and its charge is 1.6 x
1019 C. Determine
a) the radius of the path
F=ILXB
B= 5.0
mg
(ex 5)
mg= ILXB
M = 9.1 X10
32.973 X10
IB
b) The speed of the electron
F=quXB
F= 8.918 E-30 P.9
8.918
KINDA
SLON
Transcribed Image Text:9. An electron moves in a circular path perpendicular to a constant magnetic field of magnitude 5.0 mT. The angular momentum of the electron about the center of the circle is 6.00 x 1025 J-s. The mass of the electron is 9.1 x 10 kg and its charge is 1.6 x 1019 C. Determine a) the radius of the path F=ILXB B= 5.0 mg (ex 5) mg= ILXB M = 9.1 X10 32.973 X10 IB b) The speed of the electron F=quXB F= 8.918 E-30 P.9 8.918 KINDA SLON
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