9. COMPASSthe observed and calculated data for two different transit-tape surveys:RULE. Given in the accompanying tabulations areLINELATITUDEDEPARTUREDISTANCEBEARING+N-S+E- W1-2388.08 mS 52 51'wN 00°42'ES 85 57'ES 03°04'W234.36309.322-3732.72732.678.953-4324.78477.2422.94323.974-17476.5625.53Sums1922.82 m+732.67-733.86+332.92-334.85(D)(ENL)ESL)(ZED)(EWD)LATITUDEAZIMUTHFROM SOUTHCOURSEDISTANCEDEPARTURE+ N- S+ E-W1-2180 50'116 06'25 54315 20'213 27'275 39'475.48 m475.436.922-3649. 13867.34285.58582.943-4780.22378.864-5522.48371.59367.295-6504.90421.27278.316-1311.2530.64309.74Sums3330.58 m+1182.28 -1182.45-961:80+962.26(D)(ENL)(ESL)(EED)(E WD)Forclosure,the survey after the latitudes and departures arebyto a suitable scale the adjusted traverse.set of survey data,dírection of the side of error,eachdetermine themis-and precision, ofbalancedTabulate values accordingly and drawlinearthe compass rule.

Answered: Image /qna-images/answer/07a06f6c-3bbc-485c-a08f-f41d0307ec23.jpg

9. COMPASS the observed and calculated data for two different transit- tape surveys: RULE. Given in the accompanying tabulations are LATITUDE DEPARTURE LINE DISTANCE BEARING +N -S +E -W 1-2 S 52 51'w N 00 42'E S 85 57'E S 03°04'w 388.08 m 234.36 309.32 2-3 732.72 732.67 8.95 3-4 324.78 22.94 323.97 4-1 477.24 476.56 25.53 Sums 1922.82 m +732.67 733.86 + 332.92 334.85 (D) (ENL) CESL) (EED) (EWD) AZ IMUTH FROM SOUTH COURSE DISTANCE LATITUDE DEPARTURE +N +E -W 1-2 180 50' 116° 06' 25 54' 315 20' 213 27' 275 39' 475.48 m 475.43 6.92 2-3 3-4 649. 13 285.58 582.94 378.86 867.34 780.22 371.59 4-5 522.48 367.29 5-6 504.90 421.27 278.31 6-1 311.25 30.64 309.74 Sums 3330.58 m +1182.28 -1182.45 +962.26 -961.80 (D) (ENL) (ESL) (EED) (EWD) For closure, the survey after the latitudes and departures are by the compass rule. to a suitable scale the adjusted traverse. set of survey data, dírection of the side of error, each determine the linear mis- and precision, of balanced Tabulate values accordingly and draw

9. COMPASS the observed and calculated data for two different transit- tape surveys: RULE. Given in the accompanying tabulations are LATITUDE DEPARTURE LINE DISTANCE BEARING +N -S +E -W 1-2 S 52 51'w N 00 42'E S 85 57'E S 03°04'w 388.08 m 234.36 309.32 2-3 732.72 732.67 8.95 3-4 324.78 22.94 323.97 4-1 477.24 476.56 25.53 Sums 1922.82 m +732.67 733.86 + 332.92 334.85 (D) (ENL) CESL) (EED) (EWD) AZ IMUTH FROM SOUTH COURSE DISTANCE LATITUDE DEPARTURE +N +E -W 1-2 180 50' 116° 06' 25 54' 315 20' 213 27' 275 39' 475.48 m 475.43 6.92 2-3 3-4 649. 13 285.58 582.94 378.86 867.34 780.22 371.59 4-5 522.48 367.29 5-6 504.90 421.27 278.31 6-1 311.25 30.64 309.74 Sums 3330.58 m +1182.28 -1182.45 +962.26 -961.80 (D) (ENL) (ESL) (EED) (EWD) For closure, the survey after the latitudes and departures are by the compass rule. to a suitable scale the adjusted traverse. set of survey data, dírection of the side of error, each determine the linear mis- and precision, of balanced Tabulate values accordingly and draw

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question2 Course LAT DEP DMD 2A 172.5 11.5 12.55 AB 15 11.5 BC 16.75 33.55 595.4625 CD -20.45 27.65 -815.675 DE -5.75 -13.25 -6.05 34.7875 EA 3.50 -9.65 -33.775 a. What is the length of course CD, express in 2 decimal places b. What is the departure of course EA, express in 2 decimal places c. What is the area of the traverse, express in 2 decimal places. Do not include negative sign
HM 36 Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 119.010(fixed) 35 36 37 38 39 35 123.342 118.206 118.451 120.491 118.933 09 km. DM 35 O8 km DBM 37 08 km 08 km BM 39 BM 38 0.7 km
9. COMPASS the observed and calculated data for two different transit- tape surveys: RULE. Given in the accompanying tabulations are LINE LATITUDE DEPARTURE DISTANCE BEARING +N -S +E -W 1-2 S 52 51'w N 00°42'E S 85 57'E 203°04'w 388.08m 234.36 309.32 2-3 732.72 732.67 8.95 3-4 324.78 22.94 323.97 4-1 477:24 476.56 25.53 Sums 1922.82 m +732.67 +332.92 -733.86 -334.85 (D) (ENL) ESL) (ZED) EWD) LATITUDE AZIMUTH FROM SOUTH COURSE DISTANCE DEPARTURE -W 1-2 475.48 m 180 50' 116° 06' 25 54' 315 20' 213 27' 275 39' 475.43 6.92 2-3 649. 13 285.58 582.94 378.86 3-4 867.34 780.22 371.59 4-5 522.48 367.29 5-6 504.90 421.27 278.31 6-1 311.25 30.64 309.74 Sums 3330.58 m +1182.28 -1182.45 +962.26 -961.80 (D) (ENL) (ESL) (EED) (E WD) For closure, the survey after the latitudes and departures are by to a suitable scale the adjusted traverse. each set of survey data, direction of the side of error, determine the mis- and precision, of balanced Tabulate values accordingly and draw linear the compass…
Following are the data gathered from the traverse: Lat Dep DPD 2A 399.790 0 565.388565.277 -350.184605.780 -564.112-205.360 -50.882-965.697 Express all answer unitless and with 3 decimals for A to J No new data to sav
Q.3 A level circuit is shown in figure. The survey, needed for local engineering commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were project, determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 119.010(fixed) 35 36 37 38 39 35 123.342 118.206 118.451 120.491 118.933 вм 36 0.9 km вм 35 0.8 km Фвм 37 0.8 km 0.6 km BM 39 BM 38 0.7 km
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Using the data below, compute for the Linear Error of Closure Also, Determine the adjusted latitude and departure using compass rule: Line Distance Latitude Departure Adjustment (Lat) Adjustment (Dep) Adjusted Lat Adjusted Dep 1-2 388.08 -234.363 -309.322 2-3 732.72 732.665 8.952 3-4 324.78 -22.938 323.969 4-1 477.24 -476.557 -25.531 Express all answer unitless and with 3 decimals for A to J Next
46 K/s ۱۸ من ۱۸ Q.3 A level circuit is shown in figure. The survey, needed for local engineering project, commenced at BM 35, the elevation of new benchmarks 36, 37, 38 and 39 were determined, and then the level survey was looped back to BM 35, the point of commencement. Fined the adjusted new BMs. ВМ 35 Elevation(m) 119.010(fixed) 35 36 37 38 39 35 123.342 118.206 118.451 120.491 118.933 BM 38 0.9 kg BM 35 DUM 37 08 km 06 km BM 38 سلوان 2 8:11p äc lul 21.03.06
Given the tabulated data from a transit-tape survey: LINE LENGTH Bearing S6 deg 35 mins W N 17 deg 48 mins W N 70 deg 59 mins w N 59 deg 33 mins E S 39 deg 18 mins E 1-2 445.66 m 2-3 326.73 m 3-4 434.50 m 4-5 427.00 m 5-1 301.95 m Determine the following: 1. Linear Error of Closure, the bearing of the side of error, and Relative precision 2. Adjust the traverse using the transit rule. 3. Calculate the area using DMD, DPD, and triangle methods Tabulate your answers.
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