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9. Given a = (1, 2, — 3), b = (- 12, 13, 7) then a + 3b = b. (- 35, 41, 18) a. (-11, 15, 4) c. (3, 4, 1) 10. Given a = (1, 2, – 3), b = (– 12, 13, 7), the angle between a and b is: a. 74 b. 102° c. 9° d. 96° d. (0, 0, 0)

9. Given a = (1, 2, — 3), b = (- 12, 13, 7) then a + 3b = b. (- 35, 41, 18) a. (-11, 15, 4) c. (3, 4, 1) 10. Given a = (1, 2, – 3), b = (– 12, 13, 7), the angle between a and b is: a. 74 b. 102° c. 9° d. 96° d. (0, 0, 0)

Elementary Geometry For College Students, 7e
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter6: Circles
Section6.CT: Test
Problem 5CT: Given that mAB=106 and mDC=32, find: a m1 b m2
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9. Given a = (1, 2, − 3), b = (– 12, 13, 7) then a + 3b = a. ( 11, 15, 4) b. (- 35, 41, 18) c. (3, 4, 1) 10. Given a = (1, 2, — 3), b = (- 12, 13, 7), the angle between a and b is: a. 74 b. 102° c. 9° d. 96° d. (0, 0, 0)
Transcribed Image Text:9. Given a = (1, 2, − 3), b = (– 12, 13, 7) then a + 3b = a. ( 11, 15, 4) b. (- 35, 41, 18) c. (3, 4, 1) 10. Given a = (1, 2, — 3), b = (- 12, 13, 7), the angle between a and b is: a. 74 b. 102° c. 9° d. 96° d. (0, 0, 0)
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