9160 AT notoe noitsslsA brn ibst pulley Fig. 1 ro idor no ll-idO It can be shown that the acceleration a is given by Edmbusn mg 1o C (1) M + m Of course, that is the theory. In the real world, things can get messy. Welcome to experimental physics. ben BDzaam bolood gal 0S 0 ban ,01.0.200.00.0 MI ems 3. In the limit* where M< m, what is the acceleration? beaon oitorl2 noitsisge19 dsl-919 noitsislasA bns 225M 50101 (ds) to gninnigo8 ortt 16 ou0) end In the limit where M>> m, what is the acceleration? (Hint: the answer is not zero.) 4. gunoo Isiaom awork .mergcib vbod sort odi fodsl bns weTa Meast
9160 AT notoe noitsslsA brn ibst pulley Fig. 1 ro idor no ll-idO It can be shown that the acceleration a is given by Edmbusn mg 1o C (1) M + m Of course, that is the theory. In the real world, things can get messy. Welcome to experimental physics. ben BDzaam bolood gal 0S 0 ban ,01.0.200.00.0 MI ems 3. In the limit* where M< m, what is the acceleration? beaon oitorl2 noitsisge19 dsl-919 noitsislasA bns 225M 50101 (ds) to gninnigo8 ortt 16 ou0) end In the limit where M>> m, what is the acceleration? (Hint: the answer is not zero.) 4. gunoo Isiaom awork .mergcib vbod sort odi fodsl bns weTa Meast
Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN:9781305960961
Author:Michael A. Seeds, Dana Backman
Publisher:Michael A. Seeds, Dana Backman
Chapter3: Cycles Of The Sun And Moon
Section: Chapter Questions
Problem 12RQ
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The problem is of a half atwood machine. Where a=(mg)/(m+M). Where a is acceleration, g is acceleration due to gravity and both M and m are masses as seen in the attached images. I do not understand why the answer to question 4 would not be 0.
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