A 0.5kg puck slides to the right with a speed of 1.0m/s on a frictionless surface and collided with a rock of mass M which is at rest. After the collision, the 0.5kg puck recoils to the left with a speed of 0.5m/s and the rock with the mass M moves to the right with a speed of 0.5m/s.  A.) Find M (to 4 significant figures) B.) What type of collision is this? (Justify your answer)

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter8: Momentum And Collisions
Section: Chapter Questions
Problem 5OQ: A 5-kg cart moving to the right with a speed of 6 m/s collides with a concrete wall and rebounds...
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A 0.5kg puck slides to the right with a speed of 1.0m/s on a frictionless surface and collided with a rock of mass M which is at rest. After the collision, the 0.5kg puck recoils to the left with a speed of 0.5m/s and the rock with the mass M moves to the right with a speed of 0.5m/s. 
A.) Find M (to 4 significant figures)

B.) What type of collision is this? (Justify your answer)

Expert Solution
GIVEN:

Mass of the puck, m = 0.5 kg

Velocity of puck before collision, vi = 1.0 m/s

Velocity of puck after collision, vf = 0.5 m/s

Mass of the rock, M = ?

Velocity of rock before collision, Vi = 0

Velocity of rock after collision, Vf = 0.5 m/s

(A) Find the mass of rock, M

(B) What type of collision is this?

SOLUTION PART-1:

(A) Find the mass of rock, M:

For a collision, the momentum is always conserved, that is,

The total momentum before collision = The total momentum after collision

That is,

mvi+MVi = mvf + MVf

Substituting the values for above equation,

(0.5 kg)(1.0 m/s) + M(0) = (0.5 kg)(0.5 m/s) + M(0.5 m/s)

0.5 kg m/s = 0.25 kg m/s + M(0.5 m/s)

Rearranging the equation for calculating the mass of rock, we have,

M(0.5 m/s) = (0.5-0.25) kg m/s

M = 0.250.5 kg

M = 0.5 kg

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