A 1.00 × 10º-N crate is being pushed across a level floor at aconstant speed by a force É of 3.00 x 10² N at an angle of 20.0°below the horizontal, as shown in Figure P4.23a. (a) What is thecoefficient of kinetic friction between the crate and the floor?(b) If the 3.00 × 10²N force is instead pulling the block at anangle of 20.0° above the horizontal, as shown in Figure P4.23b,what will be the acceleration of the crate? Assume that the coef-ficient of friction is the same as that found in part (a).20.0°120.0°Figure P4.23

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Asked Dec 17, 2019
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A 1.00 × 10º-N crate is being pushed across a level floor at a
constant speed by a force É of 3.00 x 10² N at an angle of 20.0°
below the horizontal, as shown in Figure P4.23a. (a) What is the
coefficient of kinetic friction between the crate and the floor?
(b) If the 3.00 × 10²N force is instead pulling the block at an
angle of 20.0° above the horizontal, as shown in Figure P4.23b,
what will be the acceleration of the crate? Assume that the coef-
ficient of friction is the same as that found in part (a).
20.0°
120.0°
Figure P4.23
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A 1.00 × 10º-N crate is being pushed across a level floor at a constant speed by a force É of 3.00 x 10² N at an angle of 20.0° below the horizontal, as shown in Figure P4.23a. (a) What is the coefficient of kinetic friction between the crate and the floor? (b) If the 3.00 × 10²N force is instead pulling the block at an angle of 20.0° above the horizontal, as shown in Figure P4.23b, what will be the acceleration of the crate? Assume that the coef- ficient of friction is the same as that found in part (a). 20.0° 120.0° Figure P4.23

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Part (0) F sin (20) F cos(20) mg Since the object is corest moving with constant speed Đ SE=O Efx=0 Fcos (20)–fk = ft= Fcos (20) = (300) cor(20) c 28(-9 N fk=2819 N 281.9 Fojuation O (HE) N = 2819 $ Mk

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For the block, EFfy F sin(20)+mg=N N= 300xsin (20) + 100 = 1l02.6 N From Equation o 2819 = 02557 Mk = (102.6

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Paret Cbl F sin(20) F Cos(20) bing fk For the block, E fy N+ F sin(20) = mg N= mg - Fsin (20) N= (000 -(300) sin (201 N= 897.39N ew tons.

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