A 10⁹-F capacitor (1 nanofarad) is charged to 50 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 6x10¹3 2; on a humid day, the resistance is 7 × 10 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? On the dry day, it will take seconds. (Type your answer in scientific notation, using the appropriate symbol from the math palette for any multiplication. Round to three decimal places as needed.)

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Chapter10: Direct-current Circuits
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A 10⁹-F capacitor (1 nanofarad) is charged to 50 V and then disconnected. One can model the charge leakage of
the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a
cold dry day, the resistance of the air gap is 6x10¹3 2; on a humid day, the resistance is 7 × 10 2. How long will it
take the capacitor voltage to dissipate to half its original value on each day?
On the dry day, it will take seconds.
(Type your answer in scientific notation, using the appropriate symbol from the math palette for any multiplication.
Round to three decimal places as needed.)
Transcribed Image Text:A 10⁹-F capacitor (1 nanofarad) is charged to 50 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 6x10¹3 2; on a humid day, the resistance is 7 × 10 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? On the dry day, it will take seconds. (Type your answer in scientific notation, using the appropriate symbol from the math palette for any multiplication. Round to three decimal places as needed.)
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