A 10 -F capacitor (100 nanofarads) is charged to 50 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 5×10¹3 2; on a humid day, the resistance is 8 x 10° 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? On the dry day, it will take seconds. (Type your answer in scientific notation, using the appropriate symbol from the math palette for any multiplication. Round to three decimal places as needed.)

A 10 -F capacitor (100 nanofarads) is charged to 50 V and then disconnected. One can model the charge leakage of the capacitor with a RC circuit with no voltage source and the resistance of the air between the capacitor plates. On a cold dry day, the resistance of the air gap is 5×10¹3 2; on a humid day, the resistance is 8 x 10° 2. How long will it take the capacitor voltage to dissipate to half its original value on each day? On the dry day, it will take seconds. (Type your answer in scientific notation, using the appropriate symbol from the math palette for any multiplication. Round to three decimal places as needed.)

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter10: Direct-current Circuits

Section: Chapter Questions

Problem 55P: An ECG monitor must have an KC time constant lessthan 1.00102s to be able to measure variations...

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