A 10.2−g sample of ethylene glycol, a car radiator coolant, loses 946 J of heat. What was the initial temperature of the ethylene glycol if the final temperature is 32.5°C? (c of ethylene glycol = 2.42 J/g·K)what is the answer in Chelp

Question
2 views

A 10.2−g sample of ethylene glycol, a car radiator coolant, loses 946 J of heat. What was the initial temperature of the ethylene glycol if the final temperature is 32.5°C? (c of ethylene glycol = 2.42 J/g·K)

what is the answer in C

help

check_circle

Step 1

Given:

Mass of ethylene glycol=10.2 g

Heat loss (q)=946 J

Final temperature=32.5oC

Specific heat capacity (c) of ethylene glycol=2.42 J/g.K

Step 2

To calculate initial temperature of ethylene glycol:

Consider an equation, where heat flow (q) of process is equal to change in enthalpy

Step 3

Calculating the initial temperature,

By substituting all t...

Want to see the full answer?

See Solution

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in