A 100.00-mL sample of 0.2000M glycine, A+ form (see structure below), was titrated with 0.2000M of NaOH. Ka1 of glycine = 3.16x10-3; Ka2 of glycine = 2.51x10-10 a) What is the pH after the addition of 100.00 mL of NaOH? (b) What is the pH after the addition of 180.00 mL of NaOH

A 100.00-mL sample of 0.2000M glycine, A+ form (see structure below), was titrated with 0.2000M of NaOH. Ka1 of glycine = 3.16x10-3; Ka2 of glycine = 2.51x10-10 a) What is the pH after the addition of 100.00 mL of NaOH? (b) What is the pH after the addition of 180.00 mL of NaOH

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter14: Principles Of Neutralization Titrations

Section: Chapter Questions

Problem 14.43QAP

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Question

A 100.00-mL sample of 0.2000M glycine, A+ form (see structure below), was titrated with 0.2000M
of NaOH. Ka1 of glycine = 3.16x10-3; Ka2 of glycine = 2.51x10-10

a) What is the pH after the addition of 100.00 mL of NaOH?
(b) What is the pH after the addition of 180.00 mL of NaOH

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