Question
Asked Oct 30, 2019
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A 10kg box slides down a 6 m long ramp that makes an angle of 25 degrees with the ground. At
the bottom of the ramp, the box is moving 1m/s. If the specific heat is 2 joules per degree kg,
How much did the temperature of the box change by and what is the coefficient of friction?

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Expert Answer

Step 1

Write the expression for conservation of energy for the given system

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mgh=-mv +Fd 1 =mv + mgdcos e 2 mgd sin e gd sin 2 gd cos

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Step 2

Substitute the values

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(1 m/s) (9.8 m/s2)(6 m) sin (25°)- 2 (9.8 m/s2(6 m) cos (250) =0.457

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Step 3

Work done by friction is converted into heat energ...

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Fd msAT Lh.gd cos AT = S

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