A 12 µF capacitor is connected to a 10 V battery so that the capacitor has initial voltage V0 = 10 V and holds initial charge q0 =120 µC. (a) While the capacitor is still connected to the battery, material with dielectric constant κ = 2 is inserted between the capacitor plates. What are the capacitor’s new C, V , and q? (b) The dielectric is removed and the capacitor, again with q0, and V0, is disconnected from the battery without being discharged. Now the dielectric is reinserted. What are the new C, V , and q? (c) In situations (a) and (b) does the electric field strength in the capacitor increase, decrease, or stay the same?
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An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
A 12 µF capacitor is connected to a 10 V battery so that the capacitor has initial voltage V0 = 10 V and holds initial charge q0 =120 µC.
(a) While the capacitor is still connected to the battery, material with dielectric constant κ = 2 is inserted between the capacitor plates. What are the capacitor’s new C, V , and q?
(b) The dielectric is removed and the capacitor, again with q0, and V0, is disconnected from the battery without being discharged. Now the dielectric is reinserted. What are the new C, V , and q?
(c) In situations (a) and (b) does the electric field strength in the capacitor increase, decrease, or stay the same?
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