# A 1200-kg car is being driven up a 5.0° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 524 N. A force →FF→ is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight −→WW→ and the normal force →FNF→N directed perpendicular to the road surface. The length of the road up the hill is 290 m. What should be the magnitude of →FF→, so that the net work done by all the forces acting on the car is +150 kJ?

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A 1200-kg car is being driven up a 5.0° hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 524 N. A force →FF→ is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight −→WW→ and the normal force →FNF→N directed perpendicular to the road surface. The length of the road up the hill is 290 m. What should be the magnitude of →FF→, so that the net work done by all the forces acting on the car is +150 kJ?

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Step 1

The equation for the net work done on the car by all the forces on the car is given by

Step 2

The equation for the net force on the car in...

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