A 190-pF capacitor and a 760-pF capacitor are both charged to 1.30 kV. They are then disconnected from the voltage source and are connected together, positive plate to negative plate and negative plate to positive plate. (a) Find the resulting potential difference across each capacitor. V190 pF = kV V760 pF = kV (b) Find the energy lost when the connections are made. eBook

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
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A 190-pF capacitor and a 760-pF capacitor are both charged to 1.30 kV. They are then disconnected from the voltage source and are connected together, positive plate to negative plate and negative
plate to positive plate.
(a) Find the resulting potential difference across each capacitor.
kV
V190 pF
V760
kV
pF
(b) Find the energy lost when the connections are made.
еВook
Transcribed Image Text:A 190-pF capacitor and a 760-pF capacitor are both charged to 1.30 kV. They are then disconnected from the voltage source and are connected together, positive plate to negative plate and negative plate to positive plate. (a) Find the resulting potential difference across each capacitor. kV V190 pF V760 kV pF (b) Find the energy lost when the connections are made. еВook
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