A 2.00 kg projectile is fired ertically upward with an initial velocity of 98.0 m/s. Find its kinetic energy, its potential energy, and the sum of its kinetic and potential energies at each of the following time: Make ground the reference level for Ep. Then use h = Vi + up t + 1/2 a-down ts to get height above ground for each of the different times, let +(up) be positive. To get the velocity of the mass at height, h, use v = square root (2 Ek / m). The velocity is given in the problem for time, t = 0. Do NOT use v = sq. root 2gh. Use the Full Conservation of Mechanical Energy equation which contains hi and hf and state the reference level used to determine hi and hf Time(s) Height, h, (m) Ep (J) Ek (J) E (J) V (m/s) 0 1 2 5 10 12 15 20
A 2.00 kg projectile is fired ertically upward with an initial velocity of 98.0 m/s. Find its kinetic energy, its potential energy, and the sum of its kinetic and potential energies at each of the following time: Make ground the reference level for Ep. Then use h = Vi + up t + 1/2 a-down ts to get height above ground for each of the different times, let +(up) be positive. To get the velocity of the mass at height, h, use v = square root (2 Ek / m). The velocity is given in the problem for time, t = 0. Do NOT use v = sq. root 2gh. Use the Full Conservation of Mechanical Energy equation which contains hi and hf and state the reference level used to determine hi and hf Time(s) Height, h, (m) Ep (J) Ek (J) E (J) V (m/s) 0 1 2 5 10 12 15 20
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter7: Conservation Of Energy
Section: Chapter Questions
Problem 21P: A 5.00-kg block is set into motion up an inclined plane with an initial speed of i = 8.00 m/s (Fig....
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A 2.00 kg projectile is fired ertically upward with an initial velocity of 98.0 m/s. Find its kinetic energy, its potential energy, and the sum of its kinetic and potential energies at each of the following time:
Make ground the reference level for Ep. Then use h = Vi + up t + 1/2 a-down ts to get height above ground for each of the different times, let +(up) be positive. To get the velocity of the mass at height, h, use v = square root (2 Ek / m). The velocity is given in the problem for time, t = 0. Do NOT use v = sq. root 2gh. Use the Full Conservation of Mechanical Energy equation which contains hi and hf and state the reference level used to determine hi and hf
| Time(s) | Height, h, (m) | Ep (J) | Ek (J) | E (J) | V (m/s) | |
| 0 | ||||||
| 1 | ||||||
| 2 | ||||||
| 5 | ||||||
| 10 | ||||||
| 12 | ||||||
| 15 | ||||||
| 20 |
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