A 200 Q resistor is connected in series with a 4.00 µF capacitor and an ac source. The voltage across the resistor is VR = 5.00 V cos [(800 rad/s) t]. What is the reactive capacitance and the instantaneous voltage across the capacitor A. Xe = 8.00 x 104 Q, vc = 2.00 x 10-5 V cos [(800 rad/s) t- T/2] B. Xc = 8.00 x 104 0, vc = 2.00 x 105 V cos [(800 rad/s) t + n/2] C. Xe =1.25 x 103 Q, vc = 31.2 V cos [(800 rad/s) t+ T/2] D. Xc =1.25 x 103 Q, vc = 31.2 V cos [(800 rad/s) t- n/2]

Physics for Scientists and Engineers: Foundations and Connections
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Chapter33: Inductors And Ac Circuits
Section: Chapter Questions
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A 200 Ω resistor is connected in series with a 4.00 μF capacitor and an ac source. The voltage across the resistor is given by vR = (5.00 V) cos [(800 rad/s) t]. What is the reactive capacitance and the instantaneous voltage across the capacitor? Refer to the image for the question, and kindly provide complete solutions.

A 200 Q resistor is connected in series with a 4.00 µF capacitor and an ac source. The voltage across the resistor is vR
= 5.00 V cos [(800 rad/s) t]. What is the reactive capacitance and the instantaneous voltage across the capacitor
A. X = 8.00 x 104 Q, vc = 2.00 x 105 V cos [(800 rad/s) t- T/2]
B. Xc = 8.00 x 104 0, vc = 2.00 x 105 v cos [(800 rad/s) t + T/2]
C. X =1.25 x 10³ Q, vc = 31.2 V cos [(800 rad/s) t + T/2]
D. Xc =1.25 x 103 Q, vc = 31.2 V cos [(800 rad/s) t - n/2]
Transcribed Image Text:A 200 Q resistor is connected in series with a 4.00 µF capacitor and an ac source. The voltage across the resistor is vR = 5.00 V cos [(800 rad/s) t]. What is the reactive capacitance and the instantaneous voltage across the capacitor A. X = 8.00 x 104 Q, vc = 2.00 x 105 V cos [(800 rad/s) t- T/2] B. Xc = 8.00 x 104 0, vc = 2.00 x 105 v cos [(800 rad/s) t + T/2] C. X =1.25 x 10³ Q, vc = 31.2 V cos [(800 rad/s) t + T/2] D. Xc =1.25 x 103 Q, vc = 31.2 V cos [(800 rad/s) t - n/2]
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