A 25.00 mL sample of a vinegar solution is diluted to 250.00 mL with water. Then a 25.00 mL aliquot of the diluted sample is titrated with strong base, requiring 22.13 mL of 0.1027 M sodium hydroxide to reach the endpoint. What is the molar concentration of acetic acid in the original sample of vinegar before the dilution? (a) 2.278×10‒3 M (b) 2.278×10‒2 M (c) 0.09091 M (d) 0.9091 M
A 25.00 mL sample of a vinegar solution is diluted to 250.00 mL with water. Then a 25.00 mL aliquot of the diluted sample is titrated with strong base, requiring 22.13 mL of 0.1027 M sodium hydroxide to reach the endpoint. What is the molar concentration of acetic acid in the original sample of vinegar before the dilution? (a) 2.278×10‒3 M (b) 2.278×10‒2 M (c) 0.09091 M (d) 0.9091 M
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.162QP: The active ingredients in an antacid tablet contained only calcium carbonate and magnesium...
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A 25.00 mL sample of a vinegar solution is diluted to 250.00 mL with water. Then a 25.00 mL aliquot of the diluted sample is titrated with strong base, requiring 22.13 mL of 0.1027 M sodium hydroxide to reach the endpoint. What is the molar concentration of acetic acid in the original sample of vinegar before the dilution?
(a) 2.278×10‒3 M
(b) 2.278×10‒2 M
(c) 0.09091 M
(d) 0.9091 M
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