A 3-phase, 50-Hz, induction motor draws 50 kW from the mains. If the stator losses are 2 kW and the rotor e.m.f. is observed to make 100 complete oscillations/ alternations per minute, determine:(a). Rotor copper loss (b). Gross mechanical output.
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A 3-phase, 50-Hz, induction motor draws 50 kW from the mains. If the stator losses are 2 kW and
the rotor e.m.f. is observed to make 100 complete oscillations/ alternations per minute, determine:(a). Rotor copper loss (b). Gross
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- A synchronous, three-phase motor, connected in Y, with a frequency of 60Hz, 2300V, has a synchronous reactance of 110 per phase. The synchronous motor is a smooth pole motor. When delivering 200HP, the efficiency is calculated to be 90%, neglecting losses in the magnetic field. The power factor angle is 15 electrical degrees. Also neglect the ohmic resistance of the windings and calculate: a) The induced excitation voltage per phase. b) The line current. c) The power factor of the synchronous motor.A 220 V, single-phase induction motor gave the following test results:Blocked-rotor test: 120 V, 9.6 A, 460 WNo-load test: 220 V, 4.6 A, 125 WThe stator winding resistance is 1.5 Ω, and during the blocked-rotor test, the starting winding is open. Determine the equivalent circuit parameters. Also, find the core, friction and windage losses.1.Show that if three phase currents, each of equal magnitude and differing in phase by 120degree, flow in a three phase winding that are 120 degree apart from each other then it willproduce a rotating magnetic field of a fixed magnitude. 2. A three phase, 5-hp, 60Hz, 115V, 4-pole induction motor is operating at rated voltage, rated frequency, and 125 percent rated load has an efficiency of 85.4 percent. The stator conductor loss, rotor copper loss and core loss are 223.2W, 153W, and 114.8W respectively.Sketch the power flow diagram, enter the given data, and determine i) shaft speed ii) shaft torque 3. Can single phase induction motor be self-started? Explain the operation of a split phase single phase induction motor?
- A four-pole, single-phase, 120 V, 60 Hz induction motor gave the following standstill impedances when tested at rated frequency:Main winding : Zm =1.5+j4 ohmsAuxiliary winding : Za =3+j6 ohmsa) Determine the value of external resistance to be inserted in series with the auxiliary winding to obtain maximum starting torque as a resistor split-phase motor.b) Determine the value of the capacitor to be inserted in series with the auxiliary winding to obtain maximum starting torque as a capacitor-start motor.c) Determine the value of the capacitor to be inserted in series with the auxiliary winding to obtain maximum starting torque per ampere of the starting current as a capacitor-start motor.d) Compare the starting torques and starting currents in parts (a), (b), and (c) expressed as per unit of the starting torque without any external element in the auxiliary circuit, when operated at 120V, 60Hz.A three-phase alternator, 20 kV, synchronous has a reactance of 10Ω and a negligible resistance. The machine draws an armature current of 150A, 0.80 pf lagging. If the steam admission is constant and field current isadjusted raising the induced emf by 25 %, find the new armature current.Find the current in the bars and end rings of a cage rotor of a 6 pole 3 phase, induction motor having 72 stator slots with 15 conductors in each slot if the stator current per phase is 20 A and rotor slots are 55. Hence find the suitable size of the cage bars and end rings.
- A 110-V, 50-Hz single phase induction motor (split -phase) has the following constants for the main and auxiliary windings: Main winding, Zm (1.2 +j 25) ohm and auxiliary winding, Z,= (12+j 5) ohm. Determine (i) total current and power factor currents at time of starting, and (ii) phase angle between the main winding current and starting winding current.1.5 A 10‐pole, 380 ‐V, 50 Hz, D‐connected three‐phase induction motor is rotating a quarry belt conveyor. The machine has the following parameters, referred to the stator, on a per phase basis: Stator Parameters Winding Resistance................0.19 Ω ......... Winding Reactance.................1.12 Ω.......... Rotor Parameters Winding Resistance......................0.29 Ω Winding Reactance.....................1.12 Ω Magnetising Reactance................................16.8 Ω Equivalent Core‐loss Resistance....................900 Ω. The friction and windage losses are 320 W. When the motor runs at its rated slip of 2.6 %. Determine: 1.5.1 The stator current. 1.5.2 Estimate the Output torque of the motor under the rated conditions. 1.5.3 The Motor…The direct axis and quadrature axis reactances of a salient pole alternator are 1.4 per unit and 1.1 per unit respectively the armature resistance is negligible. If the alternator is operating at rated condition at unity power factor then estimate its power angle fast please fast in 10 minutes
- A 50-kVA, 550-volt single phase alternator draws a field current 10 A at rated load. With the same field current, the open circuit emf and short-circuit currents are 300V and 150A. The ohmic resistance of the armature between terminals is 0.18ohm. The ratio of effective to ohmic resistance maybe taken as 1.5. Determine the regulation at 0.8 power factor lagging. *Well ExplainedA 200V, 3, star connected induction motor takes 30A at a line voltage of 35V with rotor locked. With this line voltage, power input to motor is 450W and core loss is 60W.The dc resistance between a pair of stator terminals is 0.15Ω. If the ratio of ac to dc resistance is 1.6, find the equivalent leakage reactance/phase of the motor and the stator and rotor resistance per phase.3.An induction motor has a rotor resistance and reactance at standstill of 0.1 ohm and 3.5 ohm respectively. At standstill the voltage induced to the rotor is 60volts per phase. If the slip is 5%, determine the rotor current