A 3.00-kg block starts from rest at the top of an incliné at héight yo = 2.50 m above the Floor. It slides down the frictionless incline onto the floor, and then encounters a rough part of the floor that has a coefficient of kinetic friction u = 0.500. It slides 2.00 m across this surface before the floor is again frictionless. It then slides up another frictionless incline on the other side. (There are four situations here, labeled "0" through "3".) m = 3.0 kg eirls isdi slo Sagota solsd obile bold erlt e9ob enibni 1oio arll d woH 2 orli ei (9goHk 0.509onsleib orlt to ld 2.5 m 2.0 m ? 1. What is the initial gravitational potential energy PE, of the block? (Use the floor as the reference point where PE = 0.) PE = 3K9X9.8M/52x2.5m PE 73.5 J the PEO=(mass of block)x(accelerationdue to gravitu (hijgnt af block from 2. What is the speed v, of the block just before it reaches the rough part of the flóor? block frem flcer

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
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Chapter7: Conservation Of Energy
Section: Chapter Questions
Problem 79P: A block of mass 0.500 kg is pushed against a horizontal spring of negligible mass until the spring...
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The image provides all of the information, the question I need help on states: How high up the other incline does the block slide before stopping? (Note that this is the height y3, not the distance along the slope)
A 3.00-kg block starts from rest at the top of an incline at height yo = 2.50 m above the
floor. It slides down the frictionless incline onto the floor, and then encounters a rough
part of the floor that has a coefficient of kinetic friction ux = 0.500. It slides 2.00 m across
this surface before the floor is again frictionless. It then slides up another frictionless
incline on the other side. (There are four situations here, labeled "0" through "3".)
m = 3.0 kg
eirli isdi olo S gota stoisd obila bold erlt 29ob enibni 19ho aril id wwoH 2
0.50 6 9onstaib orl to ilgl ort ei
2.5 m
2.0 m
1. What is the initial gravitational potential energy PE, of the block? (Use the floor as
the reference point where PE = 0.)
PE = 3K9x9.8m52x2.5m
PE 73.5 J]
the
PEO=(mass ,ot block)x(acceleration due to
o gravity)r
(hijgnt af block frem flaer)
2. What is the speed v, of the block just before it reaches the rough part of the floor?
KEo=0
PEotfo = 73.5 J
From conservaticn of energy
x3X Vq² = 73.5
17 m
%3D
1.5
Transcribed Image Text:A 3.00-kg block starts from rest at the top of an incline at height yo = 2.50 m above the floor. It slides down the frictionless incline onto the floor, and then encounters a rough part of the floor that has a coefficient of kinetic friction ux = 0.500. It slides 2.00 m across this surface before the floor is again frictionless. It then slides up another frictionless incline on the other side. (There are four situations here, labeled "0" through "3".) m = 3.0 kg eirli isdi olo S gota stoisd obila bold erlt 29ob enibni 19ho aril id wwoH 2 0.50 6 9onstaib orl to ilgl ort ei 2.5 m 2.0 m 1. What is the initial gravitational potential energy PE, of the block? (Use the floor as the reference point where PE = 0.) PE = 3K9x9.8m52x2.5m PE 73.5 J] the PEO=(mass ,ot block)x(acceleration due to o gravity)r (hijgnt af block frem flaer) 2. What is the speed v, of the block just before it reaches the rough part of the floor? KEo=0 PEotfo = 73.5 J From conservaticn of energy x3X Vq² = 73.5 17 m %3D 1.5
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