Answered: A 30*40 ft mat foundation is to be…

A 30*40 ft mat foundation is to be placed at 9ft depth in a saturated clay where cu=1200 lb/ft2 and phi=0.find the net ultimate bearing capacity

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter16: Shallow Foundations-bearing Capacity

Section: Chapter Questions

Problem 16.14P: Repeat Problem 16.13 with the following: Mat foundation: B = 8 m, L = 20 m, and Df = 2 m Clay: =0...

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A: Please refer the attached image for complete solution. THANK YOU !

Q: subject : Geotechnical Design Book : PRINCIPLE OF FOUNDATION ENGINEERING

A: We have been given the following information:

Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

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A 30*40 ft mat foundation is to be placed at 9ft depth in a saturated clay where cu=1200 lb/ft2 and phi=0.find the net ultimate bearing capacity

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A 2.0 m wide square foundation is placed at 0.5 m depth ina saturated clay where cu= 40 kN/m2 and delta=19.0 kN/m3 .There is a very stiff stratum present at 1.0 m below the foundation. Determine the ultimate bearing capacity using Buisman’s (1940) equation.
A 1m deep foundation is placed on a soil of unit weight 20 kN/m3 and ultimate bearing capacity of 300 kN/m2. Determine the net safe bearing capacity for a factor of safety of 2.5
A continuous foundation with a width of 1 m is located on a slope made of clay soil. Refer to Figure 5.19 and let Df = 1 m, H = 4 m, b = 2 m, γ = 16.8 kN/m3, c = cu = 68 kN/m2, Φ= 0, and β = 60°.a. Determine the allowable bearing capacity of the foundation. Let FS = 3.b. Plot a graph of the ultimate bearing capacity qu if b is changed from 0 to 6 m.
Refer to Figure 5.2. A square foundation measuring 1.5 m x 1.5 m is supported by a saturated clay layer of limited depth underlain by a rock layer. Given that Df = 1 m, H = 0.7 m, cu = 115 kN/m2, and γ = 18.5 kN/m3, estimate the ultimate bearing capacity of the foundation.
It is proposed to place a 9 ft 9 ft foundation at 6 ft depth in a sandy soil, where the average N60 is 25 and the unit weight is 115.0 lb/ft3. Using Meyerhofs expressions presented in Section 9.6, estimate the allowable net pressure that would give 1.2 in. of settlement.
A 2.0 m wide continuous foundation carries a wall load of 350 kN/m in a clayey soil where = 19.0 kN/m3, c = 5.0 kN/m2, and = 23. The foundation depth is 1.5 m. Determine the factor of safety of this foundation using Eq. (6.28).
A 2.0 m wide strip foundation is placed in sand at 1.0 m depth. The properties of the sand are: γ = 19.5 kN/m3, c′ = 0, and ф′ = 34°. Determine the maximum wall load that the foundation can carry, with a factor of safety of 3.0, using Terzaghi’s original bearing capacity equation with his bearing capacity factors, and Meyerhof’s general bearing capacity equation with shape, depth, and inclination factors from Table 6.3.
A column foundation (Figure P6.9) is 3 m × 2 m in plan. Given: Df = 1.5 m, ф′ = 25°, c′ = 70 kN/m2. Using Eq. (6.28) and FS = 3, determine the net allowable load [see Eq. (6.24)] the foundation could carry. Figure P6.9
A square column foundation has to carry a gross allowable load of 1805 kN (FS = 3). Given: Df = 1.5 m, =15.9 kN/m3, = 34, and c = 0. Use Terzaghis equation to determine the size of the foundation (B). Assume general shear failure.
Consider a continuous foundation of width B = 1.4 m on a sand deposit with c = 0, = 38, and = 17.5 kN/m3. The foundation is subjected to an eccentrically inclined load (see Figure 6.33). Given: load eccentricity e = 0.15 m, Df = 1 m, and load inclination = 18. Estimate the failure load Qu(ei) per unit length of the foundation a. for a partially compensated type of loading [Eq. (6.89)] b. for a reinforced type of loading [Eq. (6.90)]
Repeat Problem 16.13 with the following: Mat foundation: B = 8 m, L = 20 m, and Df = 2 m Clay: =0 and cu = 130 kN/m2 16.13 A mat foundation measuring 14 m 9 m has to be constructed on a saturated clay. For the clay, cu = 93 kN/m2 and =0. The depth, Df, for the mat foundation is 2 m. Determine the net ultimate bearing capacity.
The applied load on a shallow square foundation makes an angle of 20° with the vertical. Given: B = 5 ft, Df = 3 ft, γ = 115 lb/ft3, ф′ = 25°, and c′ = 600 lb/ft2. Use FS = 3 and determine the gross inclined allowable load. Use Eq. (6.28).