A 380 volts, 3 phases, 50 Hz, 10 pole motor is driving a water pump (Torque is proportional to speed) at 580 rpm and 80% system efficiency and consuming 200 kWh a day in 10 hours. It is required to reduce the water flow to 60% for 6 of the 10 hours using an AC drive. a) Find the synchronous speed, speed, slip speed, frequency, voltage, torque and power. Draw the T-n curve for the two operating points. b) Compare between the energy consumed per year using an AC drive or a throttle valve, if the pump operates 300 days and the energy cost is 0.5 LE/kWh. c) What is the maximum cost of the drive if its cost has to be recovered in 2 years from energy savings?

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A 380 volts, 3 phases, 50 Hz, 10 pole motor is driving a water pump (Torque is
proportional to speed) at 580 rpm and 80% system efficiency and consuming 200 kWh a
day in 10 hours. It is required to reduce the water flow to 60% for 6 of the 10 hours using
an AC drive.
a) Find the synchronous speed, speed, slip speed, frequency, voltage, torque and
power. Draw the T-n curve for the two operating points.
b) Compare between the energy consumed per year using an AC drive or a throttle
valve, if the pump operates 300 days and the energy cost is 0.5 LE/kWh.
c) What is the maximum cost of the drive if its cost has to be recovered in 2 years
from energy savings?
Transcribed Image Text:A 380 volts, 3 phases, 50 Hz, 10 pole motor is driving a water pump (Torque is proportional to speed) at 580 rpm and 80% system efficiency and consuming 200 kWh a day in 10 hours. It is required to reduce the water flow to 60% for 6 of the 10 hours using an AC drive. a) Find the synchronous speed, speed, slip speed, frequency, voltage, torque and power. Draw the T-n curve for the two operating points. b) Compare between the energy consumed per year using an AC drive or a throttle valve, if the pump operates 300 days and the energy cost is 0.5 LE/kWh. c) What is the maximum cost of the drive if its cost has to be recovered in 2 years from energy savings?
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