A 392 NN wheel comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at 23.5 rad/srad/s. The radius of the wheel is 0.600 mm, and its moment of inertia about its rotation axis is 0.800MR2MR2. Friction does work on the wheel as it rolls up the hill to a stop, a height hh above the bottom of the hill; this work has absolute value 2600 JJ. Calculate hh. 2. Two vectors A⃗A→ and B⃗B→ have magnitude AA = 2.93 and BB = 3.03. Their vector product is A⃗×B⃗A→×B→ = -5.02 k^k^ + 1.94 i^i^. What is the angle between A⃗A→ and B⃗?B→? Express your answer in degrees.
A 392 NN wheel comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at 23.5 rad/srad/s. The radius of the wheel is 0.600 mm, and its moment of inertia about its rotation axis is 0.800MR2MR2. Friction does work on the wheel as it rolls up the hill to a stop, a height hh above the bottom of the hill; this work has absolute value 2600 JJ. Calculate hh. 2. Two vectors A⃗A→ and B⃗B→ have magnitude AA = 2.93 and BB = 3.03. Their vector product is A⃗×B⃗A→×B→ = -5.02 k^k^ + 1.94 i^i^. What is the angle between A⃗A→ and B⃗?B→? Express your answer in degrees.
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter10: Rotational Motion
Section: Chapter Questions
Problem 50P: A disk with moment of inertia I1 rotates about a frictionless, vertical axle with angular speed i. A...
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1. A 392 NN wheel comes off a moving truck and rolls without slipping along a highway. At the bottom of a hill it is rotating at 23.5 rad/srad/s. The radius of the wheel is 0.600 mm, and its moment of inertia about its rotation axis is 0.800MR2MR2. Friction does work on the wheel as it rolls up the hill to a stop, a height hh above the bottom of the hill; this work has absolute value 2600 JJ. Calculate hh.
2. Two vectors A⃗A→ and B⃗B→ have magnitude AA = 2.93 and BB = 3.03. Their vector product is A⃗×B⃗A→×B→ = -5.02 k^k^ + 1.94 i^i^. What is the angle between A⃗A→ and B⃗?B→?
Express your answer in degrees.
PLEASEEEEEEEEEEE PLEASE ANSWER BOTH PLEASEEEE
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