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A 4 m long ladder is resting against a vertical wall when it suddenly starts to slide down the wall. If 0 is the angle that the bottom of the ladder makes with the ground, what is the rate of change of this angle (in radians per second) if the top of the ladder is sliding down the wall at a rate of 0.25 m/s, when the top of the ladder is 3 m above the ground? O a) d = rad/s 4√5 b) de = rad/s 2√7 = rad/s 4√7 d) = -√rad/s

A 4 m long ladder is resting against a vertical wall when it suddenly starts to slide down the wall. If 0 is the angle that the bottom of the ladder makes with the ground, what is the rate of change of this angle (in radians per second) if the top of the ladder is sliding down the wall at a rate of 0.25 m/s, when the top of the ladder is 3 m above the ground? O a) d = rad/s 4√5 b) de = rad/s 2√7 = rad/s 4√7 d) = -√rad/s

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 18EQ
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A 4 m long ladder is resting against a vertical wall when it suddenly starts to slide down the wall. If 0 is the angle that the bottom of the ladder makes with the ground, what is the rate of change of this angle (in radians per second) if the top of the ladder is sliding down the wall at a rate of 0.25 m/s, when the top of the ladder is 3 m above the ground? a) dt = 4/5 rad/s 4√5 b) = -√rad/s = rad/s 4√7 Od)=-rad/s ==
Transcribed Image Text:A 4 m long ladder is resting against a vertical wall when it suddenly starts to slide down the wall. If 0 is the angle that the bottom of the ladder makes with the ground, what is the rate of change of this angle (in radians per second) if the top of the ladder is sliding down the wall at a rate of 0.25 m/s, when the top of the ladder is 3 m above the ground? a) dt = 4/5 rad/s 4√5 b) = -√rad/s = rad/s 4√7 Od)=-rad/s ==
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