A 4-pole, 3-phase, Y-connected induction motor is rated 60HZ, 208V . Its parameters are Rs 120m2, R, 290m2, Xm = 4172, X15 700m2, X, = 1.242. It is operating from rated voltage and frequency. For the purposes of testing, it is connected as shown in class to a DC machine, which serves as a generator. This DC machine has resistance R = 0.52 and constant K = 1.5V s. It is connected to a variable voltage source. Calculate the

A 4-pole, 3-phase, Y-connected induction motor is rated 60HZ, 208V . Its parameters are Rs 120m2, R, 290m2, Xm = 4172, X15 700m2, X, = 1.242. It is operating from rated voltage and frequency. For the purposes of testing, it is connected as shown in class to a DC machine, which serves as a generator. This DC machine has resistance R = 0.52 and constant K = 1.5V s. It is connected to a variable voltage source. Calculate the

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A 200V, 3, star connected induction motor takes 30A at a line voltage of 35V with rotor locked. With this line voltage, power input to motor is 450W and core loss is 60W.The dc resistance between a pair of stator terminals is 0.15Ω. If the ratio of ac to dc resistance is 1.6, find the equivalent leakage reactance/phase of the motor and the stator and rotor resistance per phase.
The stator resistance of a 1-phase induction motor is 2.5 ohm and its leakage reactance is 2.0 ohm. Onno-load, the motor takes 4 A at 96 V and at 0.25 lagging power factor. The no-load friction andwindage loss is negligible. Under the blocked-rotor condition, the input power is 130 W at 6 A and42 V. obtain the equivalent circuit parameters.
A 480V, 60Hz, six-pole, Y connected cage rotor induction motor has the followingparameters in ohms per phase referred to the stator: R1=0.5Ω X1=1.1Ω R2=0.45ΩX2=0.6Ω Xm=30Ω The total rotational losses (friction, windage, and core losses) are 1100W and are assumedto be constant. For a rotor slip of 2.2% at the rated voltage and rated frequency, calculate:a) Rotor speedb) Stator currentc) Complex, real, and reactive input power and the power factor of the machined) The air-gap power (Pag) and the developed mechanical power (Pconv)e) Developed electromechanical torque, and the output mechanical torquef) Efficiency
A 25 HP, 6 pole, 50 Hz, 3-phase slip ring induction motor runs at 960revolutions per minute on full load with a rotor current per phase of 35 A.Allowing 250 W for the copper loss in the short-circuiting gear, and 1000Wfor mechanical losses, find the resistance per phase of the three-phaserotor winding.
15. The main and auxiliary windings of a hypothetical 130-V, 60-Hz, split-phase motor have the following locked-rotor parameters: Rmw = 2.3 Ohms, Xmw = 3.0 Ohms, Raw = 9.25 Ohms, and Xaw = 8.2 Ohms. The motor is connected to a 130-V, 50-Hz system. Determine the capacitance, in microfarad, required in series with the auxiliary winding in order to obtain a 86 degrees phase displacement between the currents in the two windings. Correct Answer: 222.33
Equivalent circuit parameters of 3 HP (HP) 220V, 50Hz, 6 poles, split phase wound induction motor are given below. The loss of the motor is = 4W. Since the slip is s=5%; Calculate the stator current, output torque, motor speed and efficiency. R1 = 2 , R2` = 3 , X1=0 , X2` =0 , Xm=∞
A 208 V, 60 Hz, 2-pole, Y-connected induction motor is rated at 16 hp. Its equivalentcircuit components have the following values:(R1 = 0.200 ohm, X1 =0.410 ohm); (R2 = 0.120 ohm, X2 = 0.410 ohm); Xm = 15.0 ohm.Rotor slip is 4.5% at the rated voltage and frequency. Mechanical and core losses are 230Wand 200W respectively. Find (a) rotor speed (b) line current and motor p.f (c) Air-gap andconverted power (d) Induced torque.
A 380V 50Hz Δ-connected induction motor, its R2=2.5Ω, and I2=25A. For a rotor slip of 3% at rated conditions, Pconv equal:
A 480V, 60Hz, six-pole, Y connected cage rotor induction motor has the followingparameters in ohms per phase referred to the stator: R1=0.5ΩX1=1.1Ω R2=0.45ΩX2=0.6Ω Xm=30Ω The total rotational losses (friction, windage, and core losses) are 1100W and are assumedto be constant. For a rotor slip of 2.2% at the rated voltage and rated frequency, calculate:d) The air-gap power (Pag) and the developed mechanical power (Pconv)e) Developed electromechanical torque, and the output mechanical torquef) Efficiency
Three-phase induction motor, 460 V 50 Hz, 4 poles, 50 hp with Delta, operating at 3.8% slip rated torque when receives Line Voltage 460 V, 50 Hz The parameters of the equivalent circuit per phase are as follows.R1 = 0.33, X1 = X2 = 0.42 and Xm = 30 Ohm / phase.Answer the following questions by neglecting the mechanical losses, Core losses and Stray load losses.A) Value of the rotor resistance R2 B) Maximum torque and rated speed C) line current and starting torque of motor
The power input to a 500V, 50Hz, 6 pole, 3 phase squirrel cage induction motor running at975 RPM is 40kW. The stator losses are 1kW and friction and windage losses are 2kW.Find the output power of the motor.
A 220 V, single-phase induction motor gave the following test results:Blocked-rotor test: 120 V, 9.6 A, 460 WNo-load test: 220 V, 4.6 A, 125 WThe stator winding resistance is 1.5 Ω, and during the blocked-rotor test, the starting winding is open. Determine the equivalent circuit parameters. Also, find the core, friction and windage losses.