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A 4-pound weight is hung on a spring and stretches it 1 foot. The mass spring system is then put into motion in a medium offering a damping force numerically equal to the velocity. If the mass is pulled down 6 inches from equilibrium and released, the initial value problem describing the position, x(t), of the mass at time t is O z" – 8x' +32x 0, x (0) = 6, a' (0) = 0 O x" + 8x' +32x = 0, x (0) = 6, x' (0) = 0 O x" – 8x' +32x = 0, x (0) = , a' (0) = 0 O a" + 8a' + 32 = 0, a (0) = , a' (0) = 0

A 4-pound weight is hung on a spring and stretches it 1 foot. The mass spring system is then put into motion in a medium offering a damping force numerically equal to the velocity. If the mass is pulled down 6 inches from equilibrium and released, the initial value problem describing the position, x(t), of the mass at time t is O z" – 8x' +32x 0, x (0) = 6, a' (0) = 0 O x" + 8x' +32x = 0, x (0) = 6, x' (0) = 0 O x" – 8x' +32x = 0, x (0) = , a' (0) = 0 O a" + 8a' + 32 = 0, a (0) = , a' (0) = 0

Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 18EQ
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3) Please help with following multiple choice ASAP!

A 4-pound weight is hung on a spring and stretches it 1 foot. The mass spring system is then put into motion in a medium offering a damping force numerically equal to the velocity. If the mass is pulled down 6 inches from equilibrium and released, the initial value problem describing the position, x(t), of the mass at time t is O x" – 8x' + 32x = 0, x (0) = 6, a' (0) = 0 O x" + 8x' + 32x = 0, x (0) = 6, a' (0) = 0 %3D O x" – 8x' + 32x = 0, x (0) = , a' (0) = 0 %3D O a" + 8x' + 32x = 0, x (0) = , r' (0) = 0
Transcribed Image Text:A 4-pound weight is hung on a spring and stretches it 1 foot. The mass spring system is then put into motion in a medium offering a damping force numerically equal to the velocity. If the mass is pulled down 6 inches from equilibrium and released, the initial value problem describing the position, x(t), of the mass at time t is O x" – 8x' + 32x = 0, x (0) = 6, a' (0) = 0 O x" + 8x' + 32x = 0, x (0) = 6, a' (0) = 0 %3D O x" – 8x' + 32x = 0, x (0) = , a' (0) = 0 %3D O a" + 8x' + 32x = 0, x (0) = , r' (0) = 0
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