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A 4-pound weight is hung on a spring and stretches it 1 foot. The mass spring system is then put into motion in a medium offering a damping force numerically equal to the velocity. If the mass is pulled down 6 inches from equilibrium and released, the initial value problem describing the position, x(t), of the mass at time t is x" -8x' +32x = 0, x (0) = , x' (0) = 0 6. • x" + 8x' + 32x = 0, ¤ (0) = ;, x' (0) = 0 %3D O g" + 8x' + 32x = 0, x (0) = 6, x' (0) = 0 O g" – 8x' + 32x = 0, ¤ (0) = 6, x' (0) = 0 %3D %3D

A 4-pound weight is hung on a spring and stretches it 1 foot. The mass spring system is then put into motion in a medium offering a damping force numerically equal to the velocity. If the mass is pulled down 6 inches from equilibrium and released, the initial value problem describing the position, x(t), of the mass at time t is x" -8x' +32x = 0, x (0) = , x' (0) = 0 6. • x" + 8x' + 32x = 0, ¤ (0) = ;, x' (0) = 0 %3D O g" + 8x' + 32x = 0, x (0) = 6, x' (0) = 0 O g" – 8x' + 32x = 0, ¤ (0) = 6, x' (0) = 0 %3D %3D

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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A 4-pound weight is hung on a spring and stretches it 1 foot. The mass spring system is then put into motion in a medium offering a damping force numerically equal to the velocity. If the mass is pulled down 6 inches from equilibrium and released, the initial value problem describing the position, x(t), of the mass at time t is x" – 8x' + 32x = 0, x (0) =, x' (0) = 0 2 x" + 8x' + 32x = 0, x (0) = ;, x' (0) = 0 %3D %3D O g" + 8x' + 32x = 0, x (0) = 6, x' (0) = 0 O g" – 8x' + 32x = 0, ¤ (0) = 6, x' (0) = 0 %3D || - %3D
Transcribed Image Text:A 4-pound weight is hung on a spring and stretches it 1 foot. The mass spring system is then put into motion in a medium offering a damping force numerically equal to the velocity. If the mass is pulled down 6 inches from equilibrium and released, the initial value problem describing the position, x(t), of the mass at time t is x" – 8x' + 32x = 0, x (0) =, x' (0) = 0 2 x" + 8x' + 32x = 0, x (0) = ;, x' (0) = 0 %3D %3D O g" + 8x' + 32x = 0, x (0) = 6, x' (0) = 0 O g" – 8x' + 32x = 0, ¤ (0) = 6, x' (0) = 0 %3D || - %3D
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