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- A centripetal-acceleration addict rides in uniform circular motion with radius r=3.00m. At one instant his acceleration is a=(600m/s2)i^+(−4.00m/s2)j^. At that instant, what are the values of (a)v.a and (b)r.aA centripetal-acceleration addict rides in uniform circular motion with period T = 1.6 s and radius r = 3.30 m. At t1 his acceleration is a→=(4.80m/s2)î+(-4.70m/s2)ĵ. At that instant, what are the values of (a)v→⋅a→ and (b)r→×a→?Assume that the earth’s orbit around the sun is circular and has a radius of 1.50 x 10 to the 8th power kilometers? (a) What is the magnitude of the orbital velocity of the earth, in meters per second? (b) What is the magnitude of the centripetal acceleration of the earth toward the sun, in meters per second squared?
- A physics student on Planet Exidor throws a ball, and it follows the parabolic trajectory shown in the figure. The ball's position is shown at 1s1s intervals until ? =3s. At ? =1s=1s, the ball's velocity is ?⃗ = (2 ?̂+ 2 ?̂) ?/?. (A) Determine the ball's velocity at t =0s. (B) Determine the ball's velocity at t =2s. (C) Determine the ball's velocity at t =3s. (D) What is the value of g on Planet Exidor? (E) What was the ball's launch angleMimi leaves home to travel 6.5mi due east. Then She goes 3mi due south and in the last leg she goes 4mi, 25degrees W of S. Give her total distance traveled, what is her displacement and my angle and direction.A car is traveling at a speed of 88 km/hr on a circular racetrack of radius 670 m. What is its centripetal acceleration in m/s2?
- A particle travels in a circular orbit of radius r = 127.9 meters. Where it's speed is changing at a rate of at=11.8 at an instant when it's speed is at v = 33.6 m/s. What is the expression for the magnitude a of the total acceleration of the particle in terms of the variables from the problem statement? a = ?A car at a traffic signal starts from rest and makes a left turn in a circular trajectory of radius 6 m reaching a speed of 9 in 2 seconds. What is the magnitude of its total acceleration at t = 2 seconds? (You do not need to provide units, just the numerical value calculated in m/s2)At the equator, the radius of the Earth is approximately 6370km. A jet flies at a very low altitude at a constant speed of v=222m/s Upon landing, the jet can produce an average deceleration of magnitude a=16.5m/s2 how long in seconds will it take the jet to circle the earth at the equator
- A ball swings counterclockwise in a vertical circle at the end of a rope 1.50 m long. When the ball is 36.9° past the lowest point on its way up, its total acceleration is (-22.5 î + 20.2 ĵ ) m/s2. For that instant, (a) sketch a vectordiagram showing the components of its acceleration, (b) determine the magnitude of its radial acceleration, and (c) determine the speed and velocity of the ball.For an object undergoing a uniform circular motion with radius 5.7 m and period 4.35 sec, the centripetal acceleration (m/s2) is:At the equator, the radius of the Earth is approximately 6370 km. A jet flies at a very low altitude at a constant speed of v = 245 m/s. Upon landing, the jet can produce an average deceleration of a = 15.5 m/s2. How long will it take the jet, in seconds, to circle the Earth at the equator? t = What is the numeric value for the minimum landing distance, d (in meters), this jet needs to come to rest? Assume that when the jet touches the ground it is moving at the same speed as it was when it was flying. d =